DDWFTTW Turntable Test: 5 Min Video - Is It Conclusive?

In summary, this turntable and cart seem to be able to move faster than the wind, but it's not conclusive proof of DDWFTTW. There are some possible explanations for the effect, including lift.
  • #421
schroder said:
As for the cart running down wind, for some reasons nobody has provided me with a radar gun so I can measure it directly.
I've read that a few people are planning to make and test an outdoor device at the wiki forums.

Why don't you consider the Brennan torpedo as a working outdoor example?

http://en.wikipedia.org/wiki/Brennan_Torpedo

Also I tried to eliminate the frame of reference issue by restating the claim mathematically:

within a reasonable range of

|wind speed - ground speed|

a DDWFTTW cart can achieve

|cart speed - ground speed| > |wind speed - ground speed|
 
Physics news on Phys.org
  • #422
zoobyshoe said:
"Apparent crosswind"? Can you link me to some site that explains "apparent crosswind"? I googled but I found no definitions, just mostly posts by you here and on other forums.
Think of that term as my invention, then. I simply separated the apparent wind into components perpendicular to the path of the sailcraft (apparent crosswind) and in the direction of the path of the sailcraft (apparent headwind). In aerodynamics, the aerodynamic forces on a wing are also separated into components perpendicular to the path of the wing (lift) and in the direction of the wing (drag) so I decided to follow this precedent.

Note that Beta, defined as the angle of the apparent wind = atan(apparent crosswind / apparent headwind), so mathematically apparent crosswind and apparent headwind have their proper place in sailcraft discussions.

I don't understand why you aren't speaking of everything in terms of plain "apparent wind". Why "apparent crosswind" and also "apparent headwind?
Because an airfoil doesn't generate thrust from an "apparent headwind". Thrust meaning the aerodynamic force in the direction of a sailcraft. Thrust can only result from a diverted apparent crosswind.

This search for slowed wind sounds very idiosyncratic and seems misleadingly incomplete. It suggests that the only operative force here is Newton's Third Law. It strikes me as essential to include Bernoulli. We aren't only applying force to the back of the sail we are also removing opposition to it from the front.
It doesn't matter how the wind is slowed down. It's just as valid to slow the wind from low pressure downwind of the airfoil as it is to slow the wind from high pressure upwind of the airfoil. The point here is that when air is accelerated in one direction, a reactive force coexists in the opposite direction, a combination of Newton's 2nd and 3rd laws.

All wind powered devices have to slow down the air in order to extract power from the air.

Because he thought to affix a tell tale, this video is the most apparently impressive I've seen:

http://www.youtube.com/watch?v=aJpdWHFqHm0&fmt=18

However, if you go to the linked address for the expanded look at the cart he specifically says it's designed to be brought up to speed as a windmill: the fan is configured to receive power from the wind from behind and transmit it to the wheels, in which case the fan blades are pitched to resist acceleration into the HH, not encourage it.
Look at the start of that video, the propeller is clearly pitched to generate thrust as it rotates counter-clockwise. Jack Goodmans' description would be better worded to state that the propeller initially acts as a bluff body, slowing the wind down due to aerodynamic drag more than by slowing the wind down due to the propeller generating thrust.

Jack's cart wasn't able to self start in that video, but that wasn't his goal. He later did treadmill tests with the cart constrained by strain gauges to confirm that the cart generated forward force against the strain gauges while on a treadmill.
 
  • #423
A.T. said:
Exactly. That's why it only works if air and ground have different speeds:
- The ground puts in a small backwards force over a long distance.
- The air puts in a large forward force over a small distance.
-> The net force points forward

The large forward-force applied to the top gear by the ruler (thrust force) does two things:
a) Push the cart forward
b) Create a torque on the gear which is transmitted to the ground, where it causes a small backwards force (=breaking force).

Here is another simple analogy of DDWFTTW:
Imagine you are facing a blue picket fence which is moving very slowly to the left. Close behind it there is a brown picket fence moving also to the left but much faster than the blue one. If you now hold a stick and put it trough both fences simultaneously it will accelerate you to the right.

So you are using two things which both are moving left to accelerate yourself to the right. Thats what the DDWFTTW-cart also does with the ground (brown fence) and air (blue fence):
I've already understood and accepted all this. The cart can receive energy from the difference in speed of the surrounding media regardless of it's own speed. In principle. My objection is not to this. My objection is that, in practice, there can arise a situation where, even though there is a speed difference, it doesn't represent enough energy to do what the cart wants it to do. For example: If you strap yourself to a tree the two fences will not be able to move you.

When the cart reaches downwind speed the energy difference between the two media has been reduced to an amount equal to the energy represented by the total momentum of the cart. This is what it boils down too. The budget is unbelievably tight here and being spent fast with no deposits to make up for the withdrawals.
 
  • #424
zoobyshoe said:
When the cart reaches downwind speed the energy difference between the two media has been reduced.
Energy is tricky here, because it includes a velocity component, making it relative to a frame of reference. Note the speed differential between wind and ground is independent of the cart speed (and frame of reference).

Note also that the Brennan torpedo could reach a downstream speed of 31 mph in water, simply by pulling a pair of wires upstream to supply the power to drive the propellers. This was a real world working example of a DSFTTS (S = stream) vehicle.
 
  • #425
Jeff Reid said:
Think of that term as my invention, then. I simply separated the apparent wind into components perpendicular to the path of the sailcraft (apparent crosswind) and in the direction of the path of the sailcraft (apparent headwind). In aerodynamics, the aerodynamic forces on a wing are also separated into components perpendicular to the path of the wing (lift) and in the direction of the wing (drag) so I decided to follow this precedent.

Note that Beta, defined as the angle of the apparent wind = atan(apparent crosswind / apparent headwind), so mathematically apparent crosswind and apparent headwind have their proper place in sailcraft discussions.

Because an airfoil doesn't generate thrust from an "apparent headwind". Thrust meaning the aerodynamic force in the direction of a sailcraft. Thrust can only result from a diverted apparent crosswind.

It doesn't matter how the wind is slowed down. It's just as valid to slow the wind from low pressure downwind of the airfoil as it is to slow the wind from high pressure upwind of the airfoil. The point here is that when air is accelerated in one direction, a reactive force coexists in the opposite direction, a combination of Newton's 2nd and 3rd laws.

All wind powered devices have to slow down the air in order to extract power from the air.
So, what I hear you saying is that there is no particular advantage to analyzing it your way, it's just your taste.

Look at the start of that video, the propeller is clearly pitched to generate thrust as it rotates counter-clockwise. Jack Goodmans' description would be better worded to state that the propeller initially acts as a bluff body, slowing the wind down due to aerodynamic drag more than by slowing the wind down due to the propeller generating thrust.
You're quite right. He misspoke.
 
  • #426
Jeff Reid said:
Energy is tricky here, because it includes a velocity component, making it relative to a frame of reference. Note the speed differential between wind and ground is independent of the cart speed (and frame of reference).
You're right, I misspoke. Should have said "speed difference", not "energy difference."
 
  • #427
Jeff Reid said:
I simply separated the apparent wind into components perpendicular to the path of the sailcraft (apparent crosswind) and in the direction of the path of the sailcraft (apparent headwind). ... an airfoil doesn't generate thrust from an "apparent headwind".

zoobyshoe said:
So, what I hear you saying is that there is no particular advantage to analyzing it your way.
The advantage to my analysis is to point out the fact that an apparent headwind isn't converted into thrust, only the apparent crosswind. It also gives a clearer picture as to the meaning of Beta, which is atan(apparent crosswind / apparent headwind). Also it may not be clear that apparent crosswind is constant (for a given wind and heading), independent of the sailcraft's speed.
 
  • #428
A.T. said:
Here is another simple analogy of DDWFTTW:
Imagine you are facing a blue picket fence which is moving very slowly to the left. Close behind it there is a brown picket fence moving also to the left but much faster than the blue one. If you now hold a stick and put it trough both fences simultaneously it will accelerate you to the right.
zoobyshoe said:
For example: If you strap yourself to a tree the two fences will not be able to move you.
But there are no trees, just you with the stick(=~ cart) and two fences moving at different speeds(=~ air, ground).
zoobyshoe said:
When the cart reaches downwind speed the energy difference between the two media has been reduced to an amount equal to the energy represented by the total momentum of the cart.
zoobyshoe said:
I misspoke. Should have said "speed difference", not "energy difference."
Sorry, still doesn't make sense to me. The speed difference between the two media is constant, and is not being reduced by the speed of the cart. It seems that you are confusing physical quantities like energy, speed and momentum.
 
  • #429
schroder I think I see your problem. You are still mixing frames of reference and not seeing the experiment properly to start with. The Galilean equivalence of the cart on the treadmill is that of the cart already going downwind with the speed of the wind. If you notice in the various spork videos they hold it to get it up to speed on the treadmill. Again that would be the equivalent of using some sort of outside force (non-wind) to get the cart up to wind speed outside and then releasing it. If the cart moves up the treadmill then its speed would be its starting speed relative to the treadmill and whatever speed it generates on that short trip. In your last example you were mixing frames of reference left and right and measured the speed of the cart with respect to the wrong one. Think of it this way a line painted across the treadmill has a speed of zero with respect to it. The cart obviously is not staying with the line, it is passing it every second or so. So if it advances after release it is going faster than the wind. The treadmill is just a nice tool to see if the cart can pass that critical point of wind speed.
 
  • #430
A.T. said:
But there are no trees, just you with the stick(=~ cart) and two fences moving at different speeds(=~ air, ground).
The notion of moving a tree, here, represents some task the cart wants to perform that requires more energy than the fences can deliver.


Sorry, still doesn't make sense to me. The speed difference between the two media is constant, and is not being reduced by the speed of the cart. It seems that you are confusing physical quantities like energy, speed and momentum.
Did you get yourself up to speed on the TH, HH analysis?
 
  • #431
Jeff Reid said:
The advantage to my analysis is to point out the fact that an apparent headwind isn't converted into thrust, only the apparent crosswind. It also gives a clearer picture as to the meaning of Beta, which is atan(apparent crosswind / apparent headwind). Also it may not be clear that apparent crosswind is constant (for a given wind and heading), independent of the sailcraft's speed.
It is not clear to me why we don't just stick with the concept of apparent wind. Can't thrust be calculated from that?
 
  • #432
schroder said:
That is a major part of the problem. An honest and straight forward evaluation of this cart does not require a “physicist” who deals in abstractions. I have the utmost respect for physicists, I am only saying this problem is not complicated enough to require the services of one. It only requires a qualified test engineer with a great deal of practical experience in this sort of thing. That’s where I come in. I am now going to run a test for you and demonstrate that this cart has never run faster than the wind, cannot run faster than the wind and never will run faster than the wind.
As test director, I choose the reference frame and I choose it to be the most logical frame which can act as a reference for both the treadmill test and the outdoor test. I choose the ground as my frame of reference. It is not an “absolute” frame, so it does not violate Galilean relativity but it is easily shown to be stationary “relative” to both the moving treadmill, the cart on the treadmill, the wind which is blowing, and the cart which is moving with the wind. It is a relatively stationary reference to all the moving components in the test. I am setting up this test so the treadmill test and the outdoor test can be run simultaneously and observed by me or any other witness by standing in one position on the common ground reference. The test is conducted outdoors on a large flat surface (the “ground”). The treadmill is sitting on the ground and is enclosed by Plexiglas so as to shield it from the wind. The wind is cooperating by blowing at a nice steady velocity and is constant at 10 m/sec and is being constantly monitored by calibrated anemometers. The treadmill has a setting which has been carefully calibrated to run at exactly 10 m/sec exactly the same as the wind and both velocities referenced to the ground reference. The re is no need to read the cart’s actual velocity on the treadmill, only to demonstrate that it is either greater or lesser than the tread velocity all velocities referenced to the ground. By video analysis, it is clearly demonstrated that the cart is moving at much less than the tread velocity. I have estimated it to be at about 30% of tread velocity at most. The actual number is not important. As for the cart running down wind, for some reasons nobody has provided me with a radar gun so I can measure it directly. I don’t know why my request has been turned down. I find this very strange but I will make do. All I need is to see if there is any evidence at all if the cart is going faster than the wind or slower, all velocities measured in respect to the ground reference. As the cart is running down wind a video is recorded and on playback it clearly shows that some debris which is also being blown by the wind passes the cart at a much higher velocity than the cart is moving. All comparisons are made with respect to the ground reference. From the evidence I conclude: 1) The cart on the treadmill, being driven by the treadmill, is moving much slower than the treadmill. 2) The cart in the wind, being driven by the wind is moving much slower than the wind. All of my comparisons are with respect to one common reference and can be considered as one reference frame. I can only conclude that the evidence is overwhelmingly against the claim of DDWFTTW. In fact, I now consider the claim to be so ridiculous that I will not participate in any more discussion or debate on this matter. My findings are here presented and open to inspection to all. I consider the matter as closed.

Hi Schroder (if you’re still following this thread). I understand your sceptical position because that’s where I’ve come from. I now believe DDWFTTW is possible and proven however and that there is a very good working example of this in the Brennan Torpedo. If the carts in the videos don’t work how does the Brennan Torpedo work? Isn’t it obvious to you that they both work on essentially the same principle?

I never quite trusted that the treadmill tests were correctly representing the principle so went to the trouble of designing and building my turntable and cart to do my own testing. I believe a turntable is better for testing because it doesn’t have a limited length. Every suspicion I had about what might be falsely represented by the treadmill tests have been disproved by the turntable tests. That the cart might be storing energy for instance. I have run my cart on the turntable for over 10 minutes with no apparent loss of speed so the what the cart achieves is definitely indefinitely sustainable.

If myself or someone else built a cart and provided a video of it clearly beating bubbles floating in an outside wind would you accept this as proof? If not, what you accept as proof?
 
  • #433
swerdna said:
Hi Schroder (if you’re still following this thread). I understand
If myself or someone else built a cart and provided a video of it clearly beating bubbles floating in an outside wind would you accept this as proof? If not, what you accept as proof?

If a thing works as claimed then it can be analyzed and accounted for by the proper physics and math. None of the adherents of the device have been able to show on paper that such a device is actually possible. Support for the theoretical possibility is from other devices which aren't doing the quite the same thing. I am pretty sure I've shown it's not possible in principle: the geometry of the directly downwind situation automatically leads to a point where the cart switches from extracting energy from the relative motion of the surrounding media to being a supplier of energy to the surrounding media and it must eventually be bankrupted. And, if it can't be what it looks like then it must be something else.

My best guess is that what all the apparently successful non-motorized demonstrations show is that the stored momentum lasts longer than we guestimate it should. (No one's actually calculated.) It could be collecting and storing enough angular momentum in the rotor and wheel to maintain itself into the HH for a whole minute, or even two minutes, but it won't be sustained and will eventually slow back down till the tailwind hits it again.
 
  • #434
zoobyshoe said:
The notion of moving a tree, here, represents some task the cart wants to perform that requires more energy than the fences can deliver.

The fences have plenty of energy, just like the wind. They can accelerate any mass in the opposite direction of their movement, if the stick and the fences are strong enough.

zoobyshoe said:
It could be collecting and storing enough angular momentum in the rotor and wheel to maintain itself into the HH for a whole minute, or even two minutes, but it won't be sustained and will eventually slow back down till the tailwind hits it again.

How did the Brennan Torpedo maintain itself in this situation for 2000 yards? Stored momentum? Under water?
 
Last edited:
  • #435
zoobyshoe said:
If a thing works as claimed then it can be analyzed and accounted for by the proper physics and math. None of the adherents of the device have been able to show on paper that such a device is actually possible. Support for the theoretical possibility is from other devices which aren't doing the quite the same thing. I am pretty sure I've shown it's not possible in principle: the geometry of the directly downwind situation automatically leads to a point where the cart switches from extracting energy from the relative motion of the surrounding media to being a supplier of energy to the surrounding media and it must eventually be bankrupted. And, if it can't be what it looks like then it must be something else.

My best guess is that what all the apparently successful non-motorized demonstrations show is that the stored momentum lasts longer than we guestimate it should. (No one's actually calculated.) It could be collecting and storing enough angular momentum in the rotor and wheel to maintain itself into the HH for a whole minute, or even two minutes, but it won't be sustained and will eventually slow back down till the tailwind hits it again.
If you think that theory is more robust evidence than an actual, practical physical demonstration then I respectfully suggest that perhaps you should get out into the real world more often. :wink:

As I said earlier, stored energy was my main concern before I did testing for over 10 minutes on my turntable 10 minutes is a lot longer than the one or two you suggest. I also did a turntable test to show how the kinetic energy of a marble lasts a long time on a turntable - http://nz.youtube.com/watch?v=kc88SrMG5fA

I repeat A.T’s question - “How did the Brennan Torpedo maintain itself in this situation for 2000 yards? Stored momentum? Under water?”

And ask you the same as I asked Schroder - “If myself or someone else built a cart and provided a video of it clearly beating bubbles floating in an outside wind would you accept this as proof? If not, what you accept as proof?”
 
  • #436
We must be talking about the same thing in different ways.
Jeff Reid said:
I've seen multiple definitions for induced drag, so I'm not sure on what you mean by induced drag.

Again, there are probably many ways to explain things. The way I understand it, to gain lift, a reactionary force, from an airfoil the momentum of the air must be given a downward component. The difference in momentum vectors, arriving and leaving, results in a difference vector that is aimed, not directly downward but somewhat foreward--just simple vector subtraction. dp/dt is the force exerted by the foil on the air. The reactionary force is equal and opposite. This is ignoring frictional drag.
I've always read that the helical flow off a propeller is related to total drag, not just induced drag.
I was ignoring frictional drag.
 
Last edited:
  • #437
Jeff Reid said:
The advantage to my analysis is to point out the fact that an apparent headwind isn't converted into thrust, only the apparent crosswind. It also gives a clearer picture as to the meaning of Beta, which is atan(apparent crosswind / apparent headwind). Also it may not be clear that apparent crosswind is constant (for a given wind and heading), independent of the sailcraft's speed.

zoobyshoe said:
It is not clear to me why we don't just stick with the concept of apparent wind. Can't thrust be calculated from that?
Thrust can be calculated if the apparent wind magnitude and direction (relative to the path of the sail craft) are known. Thrust is a function of apparent crosswind which equals the apparent wind x sin(angle of apparent wind (relative to sail craft path)).

It's not clear in those articles that apparent wind is a vector, especially considering the article you linked falsely claimed that as the sailcraft's speed increased, it could turn even more downwind, get even more speed, then turn down even more downwind, get even more speed, ... , which simply isn't true.

Maximum VMG downwind (the component of speed in the direction of wind) is obtained when the heading of the sailcraft is offset (45 degrees - (Beta/2)) from true downwind. Maximum speed (regardless of direction) is obtained when the heading of the sailcraft is offset (90 degrees - Beta) from true downwind.

In either case the sailcraft can self start on the target heading and without ever changing the heading angle, eventually reach it's maximum speed. Over time as the sailcraft accelerates, the apparent crosswind remains constant, but the apparent headwind increases. Eventually the sailcraft stops accelerating when the apparent headwind increases to the speed where atan(apparent crosswind / apparent headwind) = Beta. Note that Beta depends on the sailcraft paremeters (lift versus drag of sail, "lift" versus drag of ground interface). and the true wind speed.

Thrust is a function of apparent crosswind which equals the apparent wind x sin(angle of apparent wind (relative to sail craft path)). The headwind component of the apparent wind does not generate any thrust and this is the misleading part of those artilces that refer to apparent wind without making it clear that it's a vector, or that imply that increasing apparent wind increases thrust (only an increase in apparent crosswind increases thrust).
 
Last edited:
  • #438
I’ve designed a “Brennan Boat” that uses the same principal as his torpedo except it uses the flow of water as the power source instead of pulling the cables. Or to put it more correctly, the water pulls against the cables. The cables (red) are simply anchored to a fixed point and as the boat moves away from that point the cables unwind from the spools and spin the prop. One cable feeds from the top of it’s spool, the other from the bottom of it‘s spool so they both turn in the same direction. The spools can be either directly attached to the prop shaft or via gearing if required. Hopefully the images make it clear how it works. The same setup could be used for wind tests.

http://www.accommodationz.co.nz/images/brennanboat.bmp
 
Last edited by a moderator:
  • #439
Jeff Reid said:
My issue with this is the idea of an incompressable fluid.
I think the main flaw here is that negative (below zero) pressures can be involved with formulas that deal with incompressible flows.

Phrak said:
Again, there are probably many ways to explain things. The way I understand it, to gain lift, a reactionary force, from an airfoil the momentum of the air must be given a downward component. The difference in momentum vectors, arriving and leaving, results in a difference vector that is aimed, not directly downward but somewhat foreward--just simple vector subtraction. dp/dt is the force exerted by the foil on the air. The reactionary force is equal and opposite.
There are some complications due to the fact that the air also gets angular velocities and corresponding pressure changes due to turbulence (eddies with axis parallel to wing span, vortices with axis in the direction of travel at the wing tips), but this is essentually correct.

I've seen multiple definitions for induced drag, so I'm not sure on what you mean by induced drag.

This is ignoring frictional drag.
You're missing form drag. Frictional drag is minimal. Form drag is the net aerodynamic force that occurs when any solid travels through a fluid or gas (minus the tiny amount of skin friction related drag). Induced drag is an attempt to separate form drag of an airfoil producing lift into two components. You could consider induced drag as the theoretical limit as the minimal form drag required to produce lift with an idealized perfect airfoil. The actual definitions of induced drag vary depending on what article you're reading.
 
  • #440
swerdna said:
Hopefully the images make it clear how it works. Can also be used for wind tests.
Link was broken, it's fixed now.
 
Last edited:
  • #441
Jeff Reid said:
[itex] [/itex] doesn't work here. Link to image, but it's not working either:

[b][url]http://forums.randi.org/picture.php?albumid=116&pictureid=558[/url][/b][/QUOTE]

Thanks Jeff. Works fine on my browser. I don't know how to load images to this forim so hot-Linked to the image fom a similar thread I'm running on the JREF forum.
 
  • #442
swerdna said:
Thanks Jeff. Works fine on my browser. I don't know how to load images to this forim so hot-Linked to the image fom a similar thread I'm running on the JREF forum.
I'm guessing it's working for you because you're signed into that forum. Apparently that forum doesn't allow hot linking to it's threads.
 
  • #443
Jeff Reid said:
I'm guessing it's working for you because you're signed into that forum. Apparently that forum doesn't allow hot linking to it's threads.
Thanks, Have hot-linked to some of my own webspace so should work now. How do I upload images to this forum?
 
  • #444
swerdna said:
Thanks, Have hot-linked to some of my own webspace so should work now. How do I upload images to this forum?
I don't know, but your previous post is working now. The img does work, just requires approval from an administator, your's is already working. I assume that there's an offset between boat and prop? How will you steer the boat and/or keep the wire tension equal?
 
  • #445
Jeff Reid said:
I don't know, but your previous post is working now. The img does work, just requires approval from an administator, your's is already working.
Thanks. I'm tempted to build a wind cart with this design.
 
  • #446
swerdna said:
Thanks. I'm tempted to build a wind cart with this design.
You'd need an open framework so that the prop would be exposed with minimal frame drag.
 
  • #447
Jeff Reid said:
You'd need an open framework so that the prop would be exposed with minimal frame drag.
I like that the prop isn't driven via the wheels so there can be no wheel-slip or bounce that some people think makes other carts work. I wonder if the results of testing with this design would be acceptable to those that are still sceptical?
 
  • #448
swerdna said:
I like that the prop isn't driven via the wheels so there can be no wheel-slip or bounce that some people think makes other carts work. I wonder if the results of testing with this design would be acceptable to those that are still sceptical?
There could be issues with momentum (flywheel) effects since the wind speed varies. Plus some will claim those wires are driving the motors hidden inside the spools.
 
  • #449
Jeff Reid said:
There could be issues with momentum (flywheel) effects since the wind speed varies. Plus some will claim those wires are driving the motors hidden inside the spools.
It’s easier to get a constant flow of water than air but if it was demonstrated in water some would say “but that’s water not air”. I don’t need to do any more testing for myself so I have to ask myself if I want to continue spending time and money on this. It is a fun project though.

ETA - Couldn’t this be tested just using gravity? Let the cart run down a long slop without a prop and time it. Repeat the test with a prop fitted and see if it is faster. I realize the prop wouldn’t be thrusting against gravity as it would against a wind but the prop still would have thrust against air that should make it quicker.
 
  • #450
swerdna said:
it was demonstrated in water
The issue with the water would be keeping the wires in sync as they unwound off the spools.

Couldn’t this be tested just using gravity?
The cart needs a tailwind (wind speed different than ground speed). Using the numbers from your cart as an example, when the cart is moving at 10.5 mph, the prop advance rate thorugh the air is 6 mph, 4.5 mph slower than the cart, so without a tailwind, the prop ends up slowing down the cart.
 
Last edited:
  • #451
Once again, Evasive tactics are being resorted to whenever the going gets tough for the cart, talk about anything at all except the cart. Before it was ice boats, now it is torpedos1
If you want to know the undeniable truth about the cart, I am now prepared to hand you that truth. All you need to do here is follow along and pay close attention to what I am about to present to you.
Since there is no outdoor test which can demonstrate or has demonstrated, DDWFTTW with this cart or any other cart, the proponents have presented treadmill, and now turntable evidence, which they claim proves it is happening on the treadmill and turntable. The basis of that truth lies in the principle of Galilean Relativity. Anyone who challenges the evidence is immediately attacked as not accepting or understanding Galilean Relativity, even though it is one of the simplest concepts in physics and a 6-year-old can understand it. My challenge is not based on not understanding or accepting relativity, it is based on the fact that in the case of the cart, the principle is most definitely not being applied correctly.
I will explain how Galilean Relativity should be applied in pains taking detail, so you can finally understand what is actually happening, and finally understand the limitations of this cart.
I will use three machines in my explanation. One of them is entirely hypothetical. It does not exist. It in fact cannot exist or at least it cannot perform as in my explanation. The second machine is very simple and can be made by anyone within a matter of minutes. The third machine is the cart under discussion here.
Example One: In some ways this is similar to the cart under question, in that it uses two input wheels to extract power from a treadmill. The difference is, it does not have a propeller. Instead, it has two more wheels which are drive wheels and are internally linked by a 1:1 gear system to the input wheels. The concept is simple: two wheels extract power from the moving tread, and this power is used to drive the output wheels which also sit on the tread. The idea is to use the tread to power the cart AGAINST the same tread which is driving it. As I said, you can build it, but it will not work. The reason why is clear: Just to remain stationary on the moving tread, the cart would need to do as much work on the tread as the tread is doing on the cart. It would be a Unity device and we know such a thing is not possible. To go a step further, if the cart could actually advance AGAINST the tread, moving in the opposite direction to the thread, it would be an over unity device, which we all know is not possible. The key thing to note here is this cart, with all four wheels planted on the tread, is both extracting power from the tread and it is clearly working against the same tread. If it could move at all, it would be moving in the reference frame of the tread. By simply staying stationary, it would be moving at tread velocity, in the opposite direction to the tread. If it actually moved opposite to the tread, it would be going Faster Than The Tread. That would be remarkable, because it is impossible!

Example Two: You can build this in a few minutes if you have the materials. It consists of a single axle with four wheels. Two wheels will sit on the tread, and extract power from the tread. Two larger diameter wheels sit on the floor and do work on the floor. If you do actually build this be careful as it will take off like a bat out of hell in the opposite direction to the running tread! The things to note here: It extracts power from the tread. It goes in the OPPOSITE direction to the running tread (fast). It does NOT do any work on the tread, it is clearly doing work on the FLOOR. This point is crucial, so please make sure you understand it well. If you were to claim that it is doing work on the tread, you would also have to claim it is an over unity device, and we just established that an over unity device is impossible! But since it is working against the floor, it is moving in the reference frame of the floor. If you want to know the velocity of this machine you would measure it against a mark on the floor, not on the tread!

Example Three: The little cart that can’T! This cart clearly has two wheels which sit on the tread and extract energy from the tread. It also has two more wheels which sit on the tread and do basically nothing but balance the weight as a symmetrical object so it does not fall over. It also has a propeller which interfaces with THE AIR! As the tread does work on this cart, the cart does work on the AIR. It moves in the opposite direction to the tread, but it does NO work against the tread! This is VERY important for you to finally realize. Since it does move in the opposite direction to the tread, you cannot claim it is working against the tread, because you would then be claiming it is an over unity device and we have already established that such devices do not exist! Since it working against the AIR, it is moving in the reference frame of the air and not in the reference frame of the tread. If you want to measure the velocity of this infamous little cart, you could try to mark a spot in the air and measure against that. It would be MUCH easier to mark a spot on the floor, since the air and the floor are relatively stationary to each other (Galilean relativity, remember?) So you use the floor as the legitimate frame of reference to determine what this cart is doing and NOT the tread. Once that bit of enlightenment sinks in, you realize the little cart is moving rather slowly with reference to the floor, much more slowly than the tread which is driving it. N
Now, invoking the principle of Galilean Relativity, we can say if the cart is doing about 30% of tread velocity, both measured with respect to the floor, we can expect a similar result in the wind. The cart will do about 30% of wind velocity. Actually I think 30% is a bit generous. The main point is, it will NEVER reach anywhere near wind velocity, let alone FASTER Than The Wind!

If you are still in denial about this or say “Once again Schroder, you have demonstrated a poor understanding of Galilean relativity” then you are not being honest with yourself and you are doing this Physics Forum and the Physics Community in general a great disservice. It is time to admit your mistakes and clear up this matter once and for all.
I am sending a copy of this to Admin and reporting this thread. I do NOT want it closed, I want a retraction of this ridiculous claim printed right here in this thread.
Schroder
 
  • #452
schroder said:
The test is conducted outdoors on a large flat surface (the “ground”). The treadmill is sitting on the ground and is enclosed by Plexiglas so as to shield it from the wind. The wind is cooperating by blowing at a nice steady velocity and is constant at 10 m/sec and is being constantly monitored by calibrated anemometers. The treadmill has a setting which has been carefully calibrated to run at exactly 10 m/sec exactly the same as the wind and both velocities referenced to the ground reference. The re is no need to read the cart’s actual velocity on the treadmill, only to demonstrate that it is either greater or lesser than the tread velocity all velocities referenced to the ground.

You are trolling, right ?

By video analysis, it is clearly demonstrated that the cart is moving at much less than the tread velocity. I have estimated it to be at about 30% of tread velocity at most. The actual number is not important.

The point is not that the cart is moving at "much less than the tread velocity", but rather, that it is moving *at all*. What matters is not the velocity wrt the outside ground (which is at rest in the frame of the AIR in the threadmill example), what matters is the velocity wrt the threadmill surface of course! And if it moves in the air frame (your ground frame), even the slightest bit, in the opposite direction, then OF COURSE it moves faster wrt the surface than does the air, which is NOT moving in that frame, right ? I have difficulties believing that you are being serious here. If you are, it seems that you don't even understand what the concept of "relative velocity" means (which explains at once why you have difficulties accepting a proof that is based upon galilean relativity).
DWFTTW doesn't mean that the cart is going faster than the wind in just any frame of your liking (which would be an easily disproved statement: in the frame of the cart, the velocity of it is zero, and hence smaller than any other0. DWFTTW means that the *relative velocity* of the cart and the surface on which it rides is larger than the *relative velocity* of the air and said surface. Or, differently formulated, that *in the frame of the surface on which the cart runs* the velocity of the cart is larger than that of the air (called "wind").

But I have difficulties believing you don't understand this. I think you are trolling, honestly.

From the evidence I conclude: 1) The cart on the treadmill, being driven by the treadmill, is moving much slower than the treadmill.

Again, if you acknowledge that it moves *at all* then you have your proof, because the motion of the cart (in the outside ground frame) is the *surplus* velocity over that of the wind.

2) The cart in the wind, being driven by the wind is moving much slower than the wind. All of my comparisons are with respect to one common reference and can be considered as one reference frame. I can only conclude that the evidence is overwhelmingly against the claim of DDWFTTW. In fact, I now consider the claim to be so ridiculous that I will not participate in any more discussion or debate on this matter. My findings are here presented and open to inspection to all. I consider the matter as closed.

I agree that the outdoor test videos are not conclusive at all, and that's why lab tests (turntable and threadmill tests) are much better, because the environment is much more controlled (and there's no discussion about the relative velocity of the air and the surface).

You still haven't answered my post with the train... I would like to see where you switch from yes to no ; although I guess it will be at the point when the train is moving, given what you wrote above, because visibly you don't accept the concept of relative velocity.
 
  • #453
vanesch said:
Again, if you acknowledge that it moves *at all* then you have your proof, because the motion of the cart (in the outside ground frame) is the *surplus* velocity over that of the wind.



I agree that the outdoor test videos are not conclusive at all, and that's why lab tests (turntable and threadmill tests) are much better, because the environment is much more controlled (and there's no discussion about the relative velocity of the air and the surface).

You still haven't answered my post with the train... I would like to see where you switch from yes to no ; although I guess it will be at the point when the train is moving, given what you wrote above, because visibly you don't accept the concept of relative velocity.

Read my post directly above yours and admit your error!
 
  • #454
schroder said:
Example One: In some ways this is similar to the cart under question, in that it uses two input wheels to extract power from a treadmill. The difference is, it does not have a propeller. Instead, it has two more wheels which are drive wheels and are internally linked by a 1:1 gear system to the input wheels. The concept is simple: two wheels extract power from the moving tread, and this power is used to drive the output wheels which also sit on the tread. The idea is to use the tread to power the cart AGAINST the same tread which is driving it. As I said, you can build it, but it will not work. The reason why is clear: Just to remain stationary on the moving tread, the cart would need to do as much work on the tread as the tread is doing on the cart. It would be a Unity device and we know such a thing is not possible. To go a step further, if the cart could actually advance AGAINST the tread, moving in the opposite direction to the thread, it would be an over unity device, which we all know is not possible. The key thing to note here is this cart, with all four wheels planted on the tread, is both extracting power from the tread and it is clearly working against the same tread. If it could move at all, it would be moving in the reference frame of the tread. By simply staying stationary, it would be moving at tread velocity, in the opposite direction to the tread. If it actually moved opposite to the tread, it would be going Faster Than The Tread. That would be remarkable, because it is impossible!

The reason why this doesn't work is because the power you extract from the thread with the first set of wheels is given by the force F1 which acts upon it as P1 = v1 x F1, where v1 is the relative velocity between the first set of wheels and the cart. Now, in order for you to have net traction forward, you would need to deliver a force to the second set of wheels F2, which is bigger (to overcome drag and so on), so you would need to deliver power P2 = v2 x F2. Here, v2 is the relative velocity between the second set of wheels and the surface. The problem is that because v1 = v2 here (the wheels are on a surface with which they have the same relative velocities), the power to be delivered (P2) needs to be larger than what you can extract (P1), this is impossible. In fact, if your power transmission has any losses, P2 will actually be somewhat smaller than P1, and thus F2 will be smaller than F1. In other words, the net force forward, F2 - F1, will be negative, and the overall cart will actually slow down as a function of the power losses due to dissipation.

Example Two: You can build this in a few minutes if you have the materials. It consists of a single axle with four wheels. Two wheels will sit on the tread, and extract power from the tread. Two larger diameter wheels sit on the floor and do work on the floor. If you do actually build this be careful as it will take off like a bat out of hell in the opposite direction to the running tread! The things to note here: It extracts power from the tread. It goes in the OPPOSITE direction to the running tread (fast). It does NOT do any work on the tread, it is clearly doing work on the FLOOR. This point is crucial, so please make sure you understand it well. If you were to claim that it is doing work on the tread, you would also have to claim it is an over unity device, and we just established that an over unity device is impossible! But since it is working against the floor, it is moving in the reference frame of the floor. If you want to know the velocity of this machine you would measure it against a mark on the floor, not on the tread!

This is the example of the ruler and the cart.
But you can do smarter things, such as put in some gearing mechanism which inverses the rolling direction of the outside wheels.
Now, the problem with a statement like "it does work on" is that this is a frame-dependent statement. After all, what is "doing work on" ? It means that you have a force, and a displacement. You have F, and you have a displacement during a time dt. The displacement is given by dt x v. So "doing work on" is given by F x v x dt.
However, the "v" is a frame-dependent quantity. It is the velocity of the object on which force F acts, in our chosen frame of reference. If F has the same sign as v, then the thing that applies force F on our object is "doing work on" the object. But if we now look upon this from a reference frame which outruns our object, v changes sign, (while forces remain unchanged under a change of inertial reference frame), and this time, our F x v x dt has changed sign. So this time, our "force-applying thing" has not DONE work on the object, but received work from it.
So there is no absolute physical meaning to "this has done work on that". It is a frame-dependent quantity. Of course, once one fixes the frame of reference, (for instance, to the object which is "applying the force") then this can get an absolute meaning. But what matters, is that one doesn't SWITCH reference frames when doing an overall energy (or power) balance. As long as one does it within one and the same frame, then (as per energy conservation) all works out. But don't use energy contributions calculated in different frames (using different frame-dependent velocities) to make up an overall energy balance, it won't work. All energy conservation says is that, *within one and the same frame* there is an energy balance. It doesn't say that the individual contributions in that balance are the same in all reference frames.

As an example of this, look at the force of gravity acting upon a stone we throw up in the air (from the ground). In the ground frame of reference, during the upward motion of the stone, the force of gravity is acting in the opposite direction as the velocity (in this frame). As such, the stone is doing work on the earth: it is LOOSING energy because of the force of gravity (in this frame). But now look upon this in a frame that goes up twice as fast as the stone. In this frame, the force of gravity (still downward) is in the same direction as the velocity (which is downward in this frame, as our frame outruns the stone). In this frame, gravity is doing work on the stone, and the stone is GAINING energy because of it. So is gravity "doing work on" the stone, or is it "extracting energy" from the stone ? The answer to that question is frame-dependent. There are some "natural" frames of reference of course, and the most natural would be in this case the center of mass system of the stone and the earth, which is very nearly the one fixed to the surface to the earth. But I have all the rights in the world to do my calculations in the upgoing frame.There are no claims of over-unity devices necessary for this.

Also, your statement "if you want to know the velocity of this device, it would be wrt the floor and not wrt the tread" seems so bizarre to me, that I'm starting to get convinced that instead of trolling, you really don't know what "relative velocity" means.

If the question is: what is the velocity of this device with respect to the tread ?, then for sure we don't want it wrt the ground, no ? And this would be a perfectly legitimate question, no ?

Example Three: The little cart that can’T! This cart clearly has two wheels which sit on the tread and extract energy from the tread. It also has two more wheels which sit on the tread and do basically nothing but balance the weight as a symmetrical object so it does not fall over. It also has a propeller which interfaces with THE AIR! As the tread does work on this cart, the cart does work on the AIR. It moves in the opposite direction to the tread, but it does NO work against the tread!

Again, specifying what does work on what depends on what frame you look upon things. "Doing work on" is a frame-dependent concept (just as "standing still" is).

This is VERY important for you to finally realize. Since it does move in the opposite direction to the tread, you cannot claim it is working against the tread, because you would then be claiming it is an over unity device and we have already established that such devices do not exist! Since it working against the AIR, it is moving in the reference frame of the air and not in the reference frame of the tread.

These are, mechanically speaking, totally incoherent statements honestly. Saying that it is "moving in the reference frame of the air and not in the reference frame of the tread" is about the most erroneous statement one can make concerning relative motion.

If you want to measure the velocity of this infamous little cart, you could try to mark a spot in the air and measure against that. It would be MUCH easier to mark a spot on the floor, since the air and the floor are relatively stationary to each other (Galilean relativity, remember?) So you use the floor as the legitimate frame of reference to determine what this cart is doing and NOT the tread.

There are no "legitimate" and "less legitimate" reference frames.

Honestly, as I said, or you are trolling, or you haven't gotten the most basic understanding of Newtonian mechanics and galilean relativity. You have now issued a large number of totally meaningless statements regarding them, at a point where I start to get lost as to where I can have a discussion with you regarding a simple mechanical problem.

First, I thought you didn't know what a galilean transformation was, or what exactly was the principle of galilean relativity. Next, it seems that you are missing what is the concept of relative velocity (and related to that, what it means "does work on"). Now, it even seems that you don't know what a reference frame is. Where do we start ?

Once that bit of enlightenment sinks in, you realize the little cart is moving rather slowly with reference to the floor, much more slowly than the tread which is driving it. N
Now, invoking the principle of Galilean Relativity, we can say if the cart is doing about 30% of tread velocity, both measured with respect to the floor, we can expect a similar result in the wind.

Such a statement only re-enforces my previous idea.

If you are still in denial about this or say “Once again Schroder, you have demonstrated a poor understanding of Galilean relativity” then you are not being honest with yourself and you are doing this Physics Forum and the Physics Community in general a great disservice. It is time to admit your mistakes and clear up this matter once and for all.
I am sending a copy of this to Admin and reporting this thread. I do NOT want it closed, I want a retraction of this ridiculous claim printed right here in this thread.
Schroder

I think you might be in for a surprise.
 
Last edited:
  • #455
vanesch said:
I think you might be in for a surprise.

Nothing can possibly surprise me more than your refuasl to accept the facts when you see tham in front of your eyes. I have nothing more to say here. Have a nice day!
 

Similar threads

  • Other Physics Topics
2
Replies
47
Views
11K
Replies
27
Views
8K
Replies
69
Views
10K
Replies
73
Views
27K
  • Other Physics Topics
Replies
26
Views
5K
  • Astronomy and Astrophysics
Replies
4
Views
1K
Replies
11
Views
2K
  • Math Proof Training and Practice
2
Replies
48
Views
8K
  • Other Physics Topics
Replies
0
Views
737
Back
Top