- #1
ofirg
- 129
- 13
I was just wondering. According to Lorentz transformations, if two events are simultaneous in one reference frame, they will generally not be simultaneous in another.
The time difference that I get between the two events in the other reference frame is
[itex]\Delta t^{`} = \gamma\beta\Delta x \approx {\Large \frac{\beta^{3}}{2}} \Delta x[/itex]
Where the approximation assumes [itex]\beta \ll 1[/itex]
Now, for space born objects [itex]\beta \approx 3 \cdot 10^{-5}[/itex] so
[itex]\Delta t^{`} \approx 10^{-14} \Delta x[/itex] where [itex] \Delta x[/itex] is in light time.
If one takes a distance of 100 Mpc then [itex]\Delta t^{`} \approx 10 sec [/itex]
So If I have two distant transient sources that give a signal at more or less the same time on earth, a space telescope will observe them at a noticeable time difference?
The time difference that I get between the two events in the other reference frame is
[itex]\Delta t^{`} = \gamma\beta\Delta x \approx {\Large \frac{\beta^{3}}{2}} \Delta x[/itex]
Where the approximation assumes [itex]\beta \ll 1[/itex]
Now, for space born objects [itex]\beta \approx 3 \cdot 10^{-5}[/itex] so
[itex]\Delta t^{`} \approx 10^{-14} \Delta x[/itex] where [itex] \Delta x[/itex] is in light time.
If one takes a distance of 100 Mpc then [itex]\Delta t^{`} \approx 10 sec [/itex]
So If I have two distant transient sources that give a signal at more or less the same time on earth, a space telescope will observe them at a noticeable time difference?