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KennedYeti
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Homework Statement
"You're using a diffraction grating o view the 400 to 700 nm visible spectrum. Suppose you can see the spectrum through the third order. a) Show that the first and second order spectra never overlap regardless of grating spacing. b) show that the second and third order spectra always overlap.
Homework Equations
n λ = dsinΘ
The Attempt at a Solution
for violet light 400nm
sinΘv = 1 × 400⋅10^-9 / 1/400/1000 = sin^-1(400⋅10^-9 / 1/400/1000) = 9.21°
for red light 700nm
sinΘv = 1 × 700⋅10^-9 / 1/700/1000 = sin^-1(700⋅10^-9 / 1/700/1000) = 29.34°
At this point I am completely lost. Any guidance on moving forward would be greatly appreciated. Thanks