Does every elementary particle eventually decay into quarks?

In summary: This is in equilibrium, so if you are above the sphaleron rate, you can maintain a nonzero baryon excess.In summary, the conversation discusses the concept of heat death and its potential effects on elementary particles. The possibility of proton decay and its relation to baryogenesis is also explored. There is some disagreement among theorists about the possibility of baryon number non-conservation in the Standard Model, but no concrete evidence has been found. Additionally, the difference between global and local gauge symmetries in particle physics is discussed.
  • #1
zinq
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Everything in the universe that has a beginning seems to also have an end. Stars, galaxies, molecules, atoms. But what about elementary particles? In case of heat death would it become a uniform quark soup?
 
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  • #2
zinq said:
In case of heat death would it become a uniform quark soup?

Not just quarks, since those (more precisely, up and down quarks) are not the only particles that, according to the Standard Model, cannot decay into other particles. Electrons and electron neutrinos also have that property among the fermions.
 
  • #3
Why should stable nuclei decay at all?
 
  • #4
mathman said:
Why should stable nuclei decay at all?
Eventually proton decay should get rid of stable nuclei.
 
  • #5
Chalnoth said:
Eventually proton decay should get rid of stable nuclei.
Is that a given?
I thought some experiments suggested the proton decay was virtually non-existent.
 
  • #6
256bits said:
Is that a given?
I thought some experiments suggested the proton decay was virtually non-existent.
Most likely, yes. Proton decay is virtually guaranteed by simple symmetry arguments: some process created the protons, and the time reverse of that process would necessarily cause them to decay (note: it wouldn't quite be that simple, but that's the basic idea). The properties of that process may suppress it to an extremely low level (e.g. requiring a very massive intermediate particle, akin to how the masses of the weak force bosons suppresses the weak nuclear force), but simple arguments seem to indicate it's impossible to eliminate it entirely.
 
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  • #7
That makes tons of sense. I knew about the symmetry argument, but had never gone farther in depth to entertain and explore that the creation implies a destroy time reverse process.
Should have known though. Thanks for the explanation.
 
  • #8
Just to go along with the stable nuclei thing, is it not possible at all that certain "stable" nuclei have half-lives that are simply too long for us to determine?
 
  • #9
Comeback City said:
is it not possible at all that certain "stable" nuclei have half-lives that are simply too long for us to determine?

We know exactly which nuclei are stable and which are merely long lived. If there is an allowed transition with a summed mass of the daughters below that of the parent, it will occur at some rate. Possibly trillions of years, but at some rate. There are exactly 164 nuclei that will decay at some rate but their decays have not been observed, and exactly 90 stable nuclei.
 
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  • #10
Chalnoth said:
Most likely, yes. Proton decay is virtually guaranteed by simple symmetry arguments: some process created the protons, and the time reverse of that process would necessarily cause them to decay (note: it wouldn't quite be that simple, but that's the basic idea). The properties of that process may suppress it to an extremely low level (e.g. requiring a very massive intermediate particle, akin to how the masses of the weak force bosons suppresses the weak nuclear force), but simple arguments seem to indicate it's impossible to eliminate it entirely.

What arguments are used to claim that any process ever created protons?

Simple symmetry arguments would suggest that time reversal of big bang would be big crunch, yet big crunch seems not to be expected now. Time reversal of a black hole is a white hole, yet white holes are also not expected.
 
  • #11
snorkack said:
What arguments are used to claim that any process ever created protons?
They exist, and aren't balanced by anything in our universe with a negative baryon number. Look up baryogenesis if you want to see some of the current science surrounding this topic.

snorkack said:
Simple symmetry arguments would suggest that time reversal of big bang would be big crunch, yet big crunch seems not to be expected now. Time reversal of a black hole is a white hole, yet white holes are also not expected.
The difference is that proton decay is a microscopic reaction, while black holes and a "big crunch" are macroscopic.

The relevant difference between the macroscopic realm and the microscopic realm is that if something is a valid solution to the equations in the microscopic realm, it is guaranteed to happen with some frequency. So if you can go from a collection of particles that have no baryon number, and get out a result that has a net baryon number (as must have happened in the early universe), then there is some magnitude for that process to happen in reverse.
 
  • #12
Seems reasonable, but until we actually detect a baryon number non-conservation, it's a conjecture. It's possible that the universe always had a positive baryon number.
 
  • #13
The question of proton decay remains an open question in particle physics. One of the fundamental rules in particle physics is the total number of quarks minus the total number of antiquarks must not change in a decay. Given that the proton is the lightest particle that has more quarks than antiquarks, it appears to have no viable decay mode. Some theorists question whether this rule of quark conservation is necessarily inviolable, but, no violations are known.
 
  • #14
Chronos said:
The question of proton decay remains an open question in particle physics. One of the fundamental rules in particle physics is the total number of quarks minus the total number of antiquarks must not change in a decay.

There is no fundamental requirement for this in SM. SM is a QFT and as such, _local_ gauge symmetries are its fundamental building blocks.
Baryon conservation is one of accidental _global_ symmetries of the SM Lagrangian. Not local.
SM has sphalerons, which do not conserve baryon number: they convert baryons to antileptons.
 

1. What are elementary particles?

Elementary particles are the smallest known building blocks of matter. They are subatomic particles that cannot be broken down into smaller particles through any known physical process.

2. What are quarks?

Quarks are fundamental particles that make up protons and neutrons, which are the building blocks of atomic nuclei. They are also believed to be the building blocks of other particles, such as mesons and baryons.

3. Do all elementary particles decay into quarks?

No, not all elementary particles decay into quarks. Some particles, such as photons, do not have a substructure and therefore cannot decay into smaller particles.

4. Why do some elementary particles decay into quarks?

Some elementary particles decay into quarks because they are unstable and have excess energy. This excess energy is released in the form of other particles, such as quarks, during the decay process.

5. Can the decay of elementary particles into quarks be observed?

Yes, the decay of elementary particles into quarks can be observed through experiments conducted in particle accelerators, such as the Large Hadron Collider. By studying the particles produced in these collisions, scientists can gather information about the properties and behaviors of elementary particles.

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