Earth's gravitational field strength

In summary, to find the altitude above the Earth's surface where the gravitational field strength is two-thirds or one-third of its value at the surface, use the formula F=GMm/r^2 and proportional reasoning. The mass of the second object is not needed as it cancels out in the equation. The radius for each situation can be found by adding the altitude to the radius of the Earth, and then solving for the acceleration using a=9.8m/s^2 for the Earth and a=9.8/3 for the point above the Earth.
  • #1
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Homework Statement


(a) Find the altitude above the Earth's surface where Earth's gravitational field strength would be two-thirds of its value at the surface. Assume re = 6.371 multiplied by 10^3 km.
wrong check mark km
(b) Find the altitude above the Earth's surface where Earth's gravitational field strength would be one-third of its value at the surface.
wrong check mark km

[Hint: First find the radius for each situation; then recall that the altitude is the distance from the surface to a point above the surface. Use proportional reasoning.]

Homework Equations


F = GMm/r^2

The Attempt at a Solution


I have tried it and I am either calculating wrong or setting it up wrong... or both. One problem I see with the formula is that it doesn't have the mass of the second object.. so I don't know what to do there.
 
Last edited:
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  • #2
you do not need to know the mass of the second object. F=ma and the masses of the second object cancel out. a=9.8m/s^2 on Earth and at the point above the Earth a=9.8/3 let r=radius of Earth + altitude. then plug in and solve for a.
 
  • #3
Sorry but that still isn't helping me. Are you just using the F=ma formula?
 

Related to Earth's gravitational field strength

1. What is the definition of Earth's gravitational field strength?

Earth's gravitational field strength is a measurement of the force of gravity at a specific point on the Earth's surface. It is typically denoted by the symbol 'g' and is measured in units of meters per second squared (m/s²).

2. What factors affect Earth's gravitational field strength?

The main factor that affects Earth's gravitational field strength is the mass of the Earth. The more massive an object, the greater its gravitational pull. Additionally, the distance from the center of the Earth also plays a role in the strength of the gravitational field.

3. How is Earth's gravitational field strength calculated?

The formula for calculating Earth's gravitational field strength is g = G*M/r², where g is the gravitational field strength, G is the universal gravitational constant, M is the mass of the Earth, and r is the distance from the center of the Earth.

4. How does Earth's gravitational field strength vary across the planet?

The Earth's gravitational field strength is not constant across the planet. It is strongest at the poles and weakest at the equator due to the Earth's rotation and shape. It also varies slightly depending on the altitude, with a slightly higher value at higher altitudes.

5. How does Earth's gravitational field strength compare to other planets?

Earth's gravitational field strength is relatively strong compared to other planets in our solar system. It is about 9.8 m/s², while the Moon's is only 1.6 m/s² and Jupiter's is 24.8 m/s². This is due to the Earth's larger mass compared to these other bodies.

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