Elastic and Inelastic Collision problem/lab

In summary, the aim of the experiment was to calculate momentum, kinetic energy, and elasticity. The experimenter found that momentum is conserved after a collision, and used equations 1 and 3 to calculate it. They also found that kinetic energy is equal to the product of mass and speed. Elasticity was found to be proportional to the square of the momentum.
  • #1
neomah
5
0

Homework Statement


Okay, we have a lab about elastic and inelastic collision, and we have to do it in an air table/spark table that generates dots (can be like ticker tapes). We have to determine Momentum (P and P') and Kinetic Energy (Ek and Ek')

Please view my attachment.
(' = after collision)

our data:
distance
d1 = 0.21 m
d1' = 0.34 m
d2 = 0.21 m
d2' = 0.32 m

time
t1=0.3s
t1'=0.5s
t2=0.3s
t2'=1.0s

I get that everything is straightforward, but since its a lab and I have no partner, I wanted to make sure my equations and calculations are right (there's no handout to refer, or textbook examples)

I already solved the initial velocity, for the velocity after, do I use equation 1 or 3?

For solving P, we use 2 right? Or no? and we find P' using 3?

We won't be using the degrees, right?

And we don't need 4 right?

Lastly, for Ek, we use 5 to get the Ek? but what do we use/do to get Ek'? Do we use 5 or 6

Homework Equations


1 Velocity: V=d/t
2 Momentum: P=mv
3 Momentum(?)/Collision(?): m1V1 + m2V2 = m1V1' + m2V2'
4 Work: W=F(cosθ)d
5 Kinetic Energy: Ek=1/2mv2
6 Ek=Ek'

The Attempt at a Solution



I already solved the initial velocity:
V1 = 0.21/0.3
= 0.7 m/s
V2 = 0.21/0.3
= 0.7 m/s

for the velocity after, I tried doing both 1 and 3. But I got two different answers (When solving for V1' or V2', I used the V1' or V2' in the equation). So do I stick to 1?

V = d/t

V1'= 0.34/0.5
= 0.7 m/s
V2' = 0.32/1
= 0.32 m/s

The rest of the question, I am stuck. I want to continue solving but then, I realize I might screw up on parts and get zero on my lab. See, I'm getting confused on which equations to use.

I am just looking for guidelines, not answers.

I hope you guys can help me. Thanks a lot:)
 

Attachments

  • collision.png
    collision.png
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Last edited:
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  • #2
First you have to stop this focus on which equations to use and focus on the experiment itself.

What was the aim of the experiment?

For instance - if you want to see if momentum is conserved in the collision, you have to measure the momentum before the collision and measure it after the collision to see if they are the same. That's what "conserved" means.

You did not measure momentum directly, but weighed the masses and measured their positions at different times. Now you have to turn that information into momentums to compare.

You know that momentum, by definition, is mass times speed.
-- you have the mass, but need the speed :( but:

Speed, by definition, is distance over time.
-- hey, you got those too! :)

Now describe all that in math will give you: p=md/t ... expressing momentum in terms of what you know.

Got it now?

Note: you get better results if you use the maximum distances and times available.

The most common problem people have in these forums stem from agonizing too much over getting the "right" equations instead of figuring out what actually happened.
 
Last edited:
  • #3
Simon Bridge said:
First you have to stop this focus on which equations to use and focus on the experiment itself.

What was the aim of the experiment?

For instance - if you want to see if momentum is conserved in the collision, you have to measure the momentum before the collision and measure it after the collision to see if they are the same. That's what "conserved" means.

You did not measure momentum directly, but weighed the masses and measured their positions at different times. Now you have to turn that information into momentums to compare.

You know that momentum, by definition, is mass times speed.
-- you have the mass, but need the speed :( but:

Speed, by definition, is distance over time.
-- hey, you got those too! :)

Now describe all that in math will give you: p=md/t ... expressing momentum in terms of what you know.

Got it now?

Note: you get better results if you use the maximum distances and times available.

The most common problem people have in these forums stem from agonizing too much over getting the "right" equations instead of figuring out what actually happened.


That's actually true. Thanks. :) The aim of the experiment is to calculate P, P', Ek, and Ek'.

So given the masses of the two pucks of air/spark table, mpuck1 = 356.40g and mpuck2 = 180.57g

For the momentum. I got the speed = d/t.
So P1 = mv
=0.7(356.40)
=249.5

P2 = 0.7(180.57)
=126.4

am I going to the right track now?

So now, I am solving for V' either 1 or 2.
I used the elastic collision equation. 3. Is this right?

This is what I got:
356.40(0.7)2 + 180.57(0.7)2 = 356.40V1'2 + 180.57V2'2

I ended up with:
174.636 + 88.4793 = 356.40V1'2 + 180.57V2'2
263.1153 = 356.40V1'2 + 180.57V2'2
Then square root both sides? Is that right?

and I got:
16.22 = 18.88V1' + 13.44V2'

Now I am stuck. I know I could do a simple system of equations (do use it?) but I don't know what equations to use now.
 
  • #4
neomah said:
That's actually true. Thanks. :) The aim of the experiment is to calculate P, P', Ek, and Ek'.
But why? What is the point?

Presumably you will need to compare the motion against the conservation laws, so you can decide if the collision is elastic or not.
What do you expect to be the relationship between P and P', Ek and Ek'?

So given the masses of the two pucks of air/spark table, mpuck1 = 356.40g and mpuck2 = 180.57g

For the momentum. I got the speed = d/t.
So P1 = mv
=0.7(356.40)
=249.5

P2 = 0.7(180.57)
=126.4

am I going to the right track now?
So far so good.
So now, I am solving for V' either 1 or 2.
I used the elastic collision equation. 3. Is this right?
Why are you calculating the final speeds when you went to so much trouble to measure them?! What you measured is what is really happening in the real world. The formulas are just someone's theory.

Now I am stuck. I know I could do a simple system of equations (do use it?) but I don't know what equations to use now.
Did you read the bit where I told you stop thinking about finding the right equations?
You are doing it again. Stop it!

Focus on what is actually happening on the table in front of you.
That's where the physics is.

The whole point of doing experiments is to get the universe to tell you stuff about physics.
By focusing on finding the "right" equations, you are actually telling the universe what the physics should be - this will never work.

You have measured enough to find the momentum and kinetic energy, directly, both before and after the collision. Why not do that?

If the total momentum before the collision is the same as the total momentum after the collision, what does that mean?
 
  • #5


I understand your concerns about wanting to ensure the accuracy of your calculations for this lab on elastic and inelastic collisions. It is always important to double check your work and make sure you are using the correct equations and values.

Firstly, for finding the velocities after the collision, you should stick to using equation 1, V=d/t. This equation is used to calculate the velocity of an object, which is what you are trying to find. Equation 3 is used for momentum, not velocity.

For solving for momentum, you can use equation 2, P=mv. This equation relates the mass and velocity of an object to its momentum. In this case, you will use the velocities you calculated from equation 1 to find the momentum after the collision (P' in your data).

You are correct in assuming that you will not be using the degrees in your calculations. Degrees are used for measuring angles, which is not relevant to this lab.

As for the equations for kinetic energy, you are on the right track. Equation 5, Ek=1/2mv^2, is used to calculate the kinetic energy of an object. In this case, you will use the velocities you calculated from equation 1 to find the kinetic energy after the collision (Ek' in your data).

I would suggest double checking your equations and calculations to ensure they are correct. If you are still unsure, you can always consult with a teacher or classmate for clarification. Remember, it is important to understand the concepts and equations being used rather than just getting the correct answer.

I hope this helps and good luck with your lab!
 

1. What is the difference between an elastic and inelastic collision?

An elastic collision is one in which the total kinetic energy of the system is conserved, while an inelastic collision is one in which some kinetic energy is lost due to the deformation of the objects involved.

2. How can we calculate the velocities of objects after a collision?

The velocities of objects after a collision can be calculated using the conservation of momentum and the conservation of kinetic energy equations.

3. What factors affect the outcome of a collision?

The masses, velocities, and elasticity of the objects involved all affect the outcome of a collision. Other factors such as external forces and friction may also play a role.

4. What is the purpose of conducting an elastic and inelastic collision experiment?

The purpose of conducting an elastic and inelastic collision experiment is to study the principles of energy and momentum conservation, and to observe how different factors can affect the outcome of a collision.

5. How can we determine whether a collision is elastic or inelastic?

We can determine whether a collision is elastic or inelastic by calculating the total kinetic energy before and after the collision. If the total kinetic energy is conserved, the collision is elastic. If some kinetic energy is lost, the collision is inelastic.

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