Electric Field due to Capacitor Plates

In summary, the electric field at a point x away from the positive plate in a capacitor with a uniform charge density J and potential difference V applied is given by V/d - J*(d-2x)/(2*epsilon_o).
  • #1
Keano16
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Homework Statement



A capacitor consists of two plane parallel plates, separated by a distance d. The space in between is filled with a uniform charge density J. Find the electric field at a point x away from the positive plate when a potential difference V is applied.

Homework Equations





The Attempt at a Solution



I am finding it difficult to locate this point in the setup -- as in, whether it is located outside to plates or inside. I am assuming that it is the latter. I know that the field produced by an infinite plate is (charge density)/2*epsilon_o, but none of my calculations give me something that matches the answer, which happens to be:

V/d - J*(d-2x)/(2*epsilon_o)


Any help would be great.
 
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  • #2
There is a uniform charge distribution (which probably means the distribution is not a conductor) between the capacitor plates. Thus, the net electric field between the plates is E = E0 - Eind. E0 would be the electric field without the charge distribution in between (which probably correlates to the V/d in the expression) and Eind is the electric field induced by the charge distribution.
 

Related to Electric Field due to Capacitor Plates

1. What is an electric field due to capacitor plates?

An electric field due to capacitor plates is a measure of the force felt by a charged particle placed between two parallel plates of a capacitor. This force is caused by the difference in electric potential between the plates, and is responsible for the movement of charges within the capacitor.

2. How is the electric field between capacitor plates calculated?

The electric field between capacitor plates can be calculated by dividing the potential difference between the plates by the distance between them. This can be expressed mathematically as E = V/d, where E is the electric field, V is the potential difference, and d is the distance between the plates.

3. How does the distance between capacitor plates affect the electric field?

The electric field between capacitor plates is inversely proportional to the distance between them. This means that as the distance between the plates increases, the electric field decreases. This relationship can be seen in the equation E = V/d, where a larger d value will result in a smaller electric field.

4. What is the relationship between electric field and capacitance?

The capacitance of a capacitor is directly proportional to the electric field between the plates. This means that as the electric field increases, the capacitance also increases. This relationship can be seen in the equation C = Q/V, where C is capacitance, Q is charge, and V is potential difference. As the electric field (V/d) increases, the capacitance (C) also increases.

5. How does the shape and size of capacitor plates affect the electric field?

The shape and size of capacitor plates do not affect the electric field between them, as long as the distance between the plates remains the same. The electric field is determined by the potential difference and distance between the plates, and is not affected by their physical characteristics. However, the shape and size of the plates can affect the capacitance of the capacitor, which in turn can affect the amount of charge stored on the plates.

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