- #1
physics604
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1. A moving proton has 6.4 x 10-16 J of kinetic energy. The proton is accelerated by a potential difference of 5 000 V between parallel plates. The proton emerges from the parallel plates with what speed?
a) 1.3 x 106 m/s
b) 8.8 x 105 m/s
c)1.8 x 106 m/s
d) 9.8 x 105 m/s
[itex]\Delta[/itex]Ek + [itex]\Delta[/itex]Ep = 0
Eki + Ekf = -Ep
6.4×10-16 + 1/2mv2 = -Q[itex]\Delta[/itex]v
v= √ [(-1.6x10-19×-5000)-6.4x10-16 ×2 / 1.67x10-27] = 437740.5241...
My answer doesn't match with any of the responses. What did I do wrong?
a) 1.3 x 106 m/s
b) 8.8 x 105 m/s
c)1.8 x 106 m/s
d) 9.8 x 105 m/s
Homework Equations
[itex]\Delta[/itex]Ek + [itex]\Delta[/itex]Ep = 0
The Attempt at a Solution
Eki + Ekf = -Ep
6.4×10-16 + 1/2mv2 = -Q[itex]\Delta[/itex]v
v= √ [(-1.6x10-19×-5000)-6.4x10-16 ×2 / 1.67x10-27] = 437740.5241...
My answer doesn't match with any of the responses. What did I do wrong?