- #1
highflyyer
- 28
- 1
Consider the following set of equations:
##r = \cosh\rho \cos\tau + \sinh\rho \cos\varphi##
##rt = \cosh\rho \sin\tau##
##rl\phi = \sinh\rho \sin\varphi##
Is there some way to combine the equations to get rid of ##\varphi## and ##\tau## and express ##\rho## in terms of ##r, t, \phi##?
I tried the following:
##r^{2} = (\cosh\rho \cos\tau + \sinh\rho \cos\varphi)^{2}##
##r^{2}(t-l\phi)^{2} = (\cosh\rho \sin\tau - \sinh\rho \sin\varphi)^{2}##
so that we have
##r^{2} + r^{2}(t-l\phi)^{2} = \cosh^{2}\rho + \sinh^{2}\rho + 2\cos(\tau+\varphi)\sinh\rho\cosh\rho.##
The above line is not exactly what I want, because of the factor ##\cos(\tau+\varphi)##!
Is there some neat way to get rid of ##\varphi## and ##\tau## and express ##\rho## in terms of ##r, t, \phi##?
##r = \cosh\rho \cos\tau + \sinh\rho \cos\varphi##
##rt = \cosh\rho \sin\tau##
##rl\phi = \sinh\rho \sin\varphi##
Is there some way to combine the equations to get rid of ##\varphi## and ##\tau## and express ##\rho## in terms of ##r, t, \phi##?
I tried the following:
##r^{2} = (\cosh\rho \cos\tau + \sinh\rho \cos\varphi)^{2}##
##r^{2}(t-l\phi)^{2} = (\cosh\rho \sin\tau - \sinh\rho \sin\varphi)^{2}##
so that we have
##r^{2} + r^{2}(t-l\phi)^{2} = \cosh^{2}\rho + \sinh^{2}\rho + 2\cos(\tau+\varphi)\sinh\rho\cosh\rho.##
The above line is not exactly what I want, because of the factor ##\cos(\tau+\varphi)##!
Is there some neat way to get rid of ##\varphi## and ##\tau## and express ##\rho## in terms of ##r, t, \phi##?