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helloxkitty
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Homework Statement
A block of mass 7.00×10-1kg is suspended by a string which is wrapped so that it is at a radius of 5.80×10-2m from the center of a pulley. The moment of inertia of the pulley is 4.00×10-3kg*m2. There is friction as the pulley turns. The block starts from rest, and its speed after it has traveled downwards a distance of D=0.830m is 1.611m/s. Calculate the amount of energy dissipated up to that point.
given m, r, I, v, D, find Q (energy lost)
Homework Equations
mgh=U(x)
1/2Iw^2
I/2mv^2
The Attempt at a Solution
-mgh=1/2Iw^2+1/2mv^2+Q
solve for Q, get 8.15 J lost. I'm not really sure why I'm unable to get the right answer...unless 8.15 is supposed to be negative. Any thoughts? Thanks so much =)!