- #1
FaraDazed
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Homework Statement
Find an equation for the tangent plane to a surface [itex]xz^2 +x^2y-z=-1[/itex] at the point (1,-3,2).
Homework Equations
[itex]
(\vec{r}-\vec{r_p}) \cdot \nabla f(\vec{r_p}) = 0
[/itex]
The Attempt at a Solution
[/B]
First I found the gradient of the function
[itex]
\nabla f = (z^2+2xy)\hat{i} + x^2 \hat{j} + (2xz-1)\hat{k}
[/itex]
and then evaluated at (1,-3,2)
[itex]
\nabla f(\vec{r_p}) = (2^2+2(1)(-3))\hat{i} + 1^2 \hat{j} + (2(1)(2)-1)\hat{k} = (-2,1,3)
[/itex]
And then used the relation in the relevant equations section:
[itex]
(\vec{r}-\vec{r_p}) \cdot \nabla f(\vec{r_p}) = 0 \\
(x-1,y+3,z-2) \cdot (-2,1,3) = 0 \\
(-2x+2)+(y+3)+(3z-6) = 0 \\
-2x+y+3z=1
[/itex]
This is the first time I've ever done this and I am just going off of a similar example that the solution was given for. It is not exactly the same question so not sure my process is even correct. Would appreciate any help :)
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