- #1
Woolyabyss
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Homework Statement
Find all stationary points of the function
G(x, y) = (x^3)*e^(−x^2−y^2)
Homework Equations
fx=0 and fy=0
The Attempt at a Solution
Gx = 3x^2*e^(-x^2-y^2) +x^3(-2x)e^(-x^2-y^2) = e^(-x^2-y^2)(3x^2-2x^4)
Gx = 0 implies 3x^2-2x^4=0
x^2(3-2x^2)=0
hence x =0 ,+or- (3/2)^(1/2)
Gy = (-2y)(x^3)(e^(-x^2-y^2))
Gy=0
implies (-2y)(x^3)(e^(-x^2-y^2))=0
y=0 x = 0
(+or- (3/2)^(1/2), 0) are the two stationary points according to wolfram alpha but I don't understand why (o,a), where a is a real number, isn't a solution since Gx=Gy=0 when x = 0.
Any help would be appreciated.
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