- #1
B3NR4Y
Gold Member
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Homework Statement
An electron moves to the right with a speed of 0.90c in the laboratory frame. A proton moves to the left with a speed of 0.77c relative to the electron.
Using the Lorentz coordinate transformations, find the speed of the proton in the laboratory frame
Homework Equations
$$
\begin{align*}
x &= \frac{x'+ut'}{\sqrt(1-(u^2/c^2))} \\
y & = y \\
z & = z \\
t & = \frac{t'+(\frac{u}{c^2})x'}{\sqrt(1-(u^2/c^2))} \\
\end{align*}
$$
The Attempt at a Solution
I used the velocity transformation in the second part of the problem and found the speed of the proton to be 0.42c, but I'm not sure how to find it with the coordinate transforms.
I tried dividing x and t, but terms that I don't know remain and I can't get rid of them.