Find the Wronskian of solutions y1 and y2 of the equation

  • Thread starter Fatima Hasan
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    Wronskian
Great job!In summary, the conversation discusses solving a homogeneous equation using the standard form. The correct solution involves dividing by x^2 and correcting a mistake in the third term. The final solution is y'' + (3y'/x) + (3y/x^2) = 0, with P(x) = 3/x and W(x) = Cx^-3.
  • #1
Fatima Hasan
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Homework Statement


[/B]
Capture.png


Homework Equations


##W(x) = C exp (∫ P(x) dx)##
##y''+P(x)y'+g(x)=0##

The Attempt at a Solution


Divide the origin equation by (x) to get the standard form of the homogeneous equation :
##y'' +\frac{3y'}{x} - \frac{3y}{x}##
##P(x) = \frac{3}{x}##
## exp (- ∫ \frac{3}{x}##
## = exp ( -3 ln (x))##
## = x^{-3}##
##W(x) = C x^{-3} ##
Could someone check my answer please?
 

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  • #2
Fatima Hasan said:

Homework Statement


[/B]
View attachment 234516

Homework Equations


##W(x) = C exp (∫ P(x) dx)##
##y''+P(x)y'+g(x)=0##

The Attempt at a Solution


Divide the origin equation by (x)
No, you need to divide by ##x^2##
Fatima Hasan said:
to get the standard form of the homogeneous equation :
##y'' +\frac{3y'}{x} - \frac{3y}{x}##
The third term is incorrect. Also, you lost the = so you no longer have an equation.
Fatima Hasan said:
##P(x) = \frac{3}{x}##
## exp (- ∫ \frac{3}{x}##
## = exp ( -3 ln (x))##
## = x^{-3}##
##W(x) = C x^{-3} ##
Could someone check my answer please?
 
  • #3
Mark44 said:
No, you need to divide by ##x^2##
The third term is incorrect. Also, you lost the = so you no longer have an equation.
I've solved it again , here's my work :
gif.gif
 

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  • #4
Looks fine to me.
 
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What is the Wronskian?

The Wronskian is a mathematical concept used to determine the linear independence of a set of functions. It is represented by the symbol W and can be calculated using a specific formula.

How is the Wronskian used in solving equations?

The Wronskian can be used to determine if a set of solutions to a differential equation are linearly independent, which is a necessary condition for finding a unique solution. It can also be used to solve higher-order differential equations by reducing them to a system of first-order equations.

What are the steps to find the Wronskian of solutions y1 and y2?

The steps to find the Wronskian are as follows:
1. Write the solutions y1 and y2 in terms of their derivatives (y1' and y2').
2. Set up the Wronskian formula: W = y1'y2 - y2'y1.
3. Simplify the formula using algebraic operations.
4. Evaluate the Wronskian at a specific point or over a specific interval, if necessary.

Can the Wronskian be used for any type of equation?

No, the Wronskian is specifically used for linear differential equations. It cannot be used for non-linear equations.

What does the value of the Wronskian indicate?

If the Wronskian is non-zero, it indicates that the solutions y1 and y2 are linearly independent and therefore a unique solution can be found. If the Wronskian is zero, it indicates that the solutions are linearly dependent and a unique solution cannot be found.

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