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Kieran12
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Homework Statement
An optical telescope has a diameter of 1.5m. It is placed at a site with 'seeing' of 1.0''. What is the expected resolution in arcseconds from observations made with the telescope at 1000nm? Give your answer to one decimal place
Homework Equations
Theta (rads) = 1.22 * (wavelength/diametre of aperture)
Rads * 180/pi = degrees
1 degree = 1*60*60 arcseconds
The Attempt at a Solution
So far, I have used the equation:
Theta = 1.22 * (wavelength / D) (where D = diametre of aperture).
Thus using this equation I have worked out that: 1.22 * (1000 * 10-9 / 1.5) = 813.33 * 10-9 rads = 0.167 arcseconds.
Where does seeing come into all this?? Its driving me mad!