Finding the Equation of a Line Given Two Points

[mathdad]

Find an equation of the line that passes through (6, -3) and has y-intercept 8.

I know y = mx + b is the slope-intercept formula. In the formula, b represents the y-intercept. I also see that 8 is given to be b in this case.

The y-intercept can be written as (0, 8).

Do I now find the slope m?
Afterward, use one of the points and m to plug into the point-slope formula. Finally, I must isolate y.

Is this right?

 

[MarkFL]

Like you, I would begin with the slope-intercept form of a line:

\(\displaystyle y=mx+b\)

We are given $b=8$, and we know two points on the line, so we can compute the slope $m$:

\(\displaystyle m=\frac{8-(-3)}{0-6}=\)?

Then, just plug in the values for $m$ and $b$. :)

 

[mathdad]

Like you, I would begin with the slope-intercept form of a line:

\(\displaystyle y=mx+b\)

We are given $b=8$, and we know two points on the line, so we can compute the slope $m$:

\(\displaystyle m=\frac{8-(-3)}{0-6}=\)?

Then, just plug in the values for $m$ and $b$. :)

I can take it from here. Thanks.