- #1
itsmarasilly
- 24
- 0
Homework Statement
A wire carrying 15 A of current has a length of 17 cm in a magnetic field of 0.80 T. The force on a current-carrying wire in a uniform magnetic field can be found using the equation F = BIL sin θ. Find the force on the wire for each of the following angles between the wire and the magnetic field lines. ( (a) 90° )
Homework Equations
F = BIL
Sin = Opposite/Hypotenuse
17 cm / 100 = .17 m
The Attempt at a Solution
F = 15*.17*.8*sin(90)
= 1.8238 N
Last edited: