Finding the total momentum of system

In summary: Since the momentum of the system is conserved, the total momentum before and after the car starts to move must be the same. So you can use the equation Ptotal = m1v1 + m2v2 with the final momentum of the system being 0.
  • #1
Stormblessed
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2

Homework Statement



A car of mass 1500 kg is at rest on a platform of mass 3000 kg, which is also at rest. The platform has frictionless wheels attached to its bottom. The whole system is initially at rest. The car starts to move forward at a speed of 5.0 m/s with respect to the ground. (Consider all measurements with respect to the ground).

What is the momentum of the car as it starts to move?

What is the momentum of the car-platform system as the car starts to move?

Homework Equations



P = mv
Ptotal = m1v1 + m2v2[/B]

The Attempt at a Solution



I was able to solve the first question using the equation P = mv, getting a momentum of 7500 Ns for the car. I don't know how to solve for the momentum of the platform-car system, since the speed of the platform with respect to the ground is not given. [/B]
 
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  • #2
Stormblessed said:

Homework Statement



A car of mass 1500 kg is at rest on a platform of mass 3000 kg, which is also at rest. The platform has frictionless wheels attached to its bottom. The whole system is initially at rest. The car starts to move forward at a speed of 5.0 m/s with respect to the ground. (Consider all measurements with respect to the ground).

What is the momentum of the car as it starts to move?

What is the momentum of the car-platform system as the car starts to move?

Homework Equations



P = mv
Ptotal = m1v1 + m2v2[/B]

The Attempt at a Solution



I was able to solve the first question using the equation P = mv, getting a momentum of 7500 Ns for the car. I don't know how to solve for the momentum of the platform-car system, since the speed of the platform with respect to the ground is not given. [/B]
What forces act on the car-platform system?
 
  • #3
There's an thing called momentum conservation. The car+platform system started out from rest position. And 1 more hint, P=mv is actually a directional entity, i.e. vector.
 
  • #4
haruspex said:
What forces act on the car-platform system?

Force of gravity and normal force which cancel out. Is there an applied force from the car, or are there no unbalanced forces on the platform?
 
  • #5
Stormblessed said:
Is there an applied force from the car
Newton's second law: If the car accelerated, it was subject to a net force.
Newton's third law: If the car was under a force from something, that other thing was under a force from the car.

The car's tires are in contact with that "other thing".
 
  • #6
jbriggs444 said:
Newton's second law: If the car accelerated, it was subject to a net force.
Newton's third law: If the car was under a force from something, that other thing was under a force from the car.

The car's tires are in contact with that "other thing".

Since the system is isolated and initially at rest, would it mean that, according to Conservation of Momentum, that the momentum of the system after the car starts to move is 0?
 
  • #7
Stormblessed said:
Since the system is isolated and initially at rest, would it mean that, according to Conservation of Momentum, that the momentum of the system after the car starts to move is 0?

Yes. That's why it said "frictionless wheels". So that no momentum could be transferred to the ground/Earth. If the wheels were not frictionless, then the momentum of the car-platform system would not be conserved.
 
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  • #8
PeroK said:
Yes. That's why it said "frictionless wheels". So that no momentum could be transferred to the ground/Earth. If the wheels were not frictionless, then the momentum of the car-platform system would not be conserved.

And to find the velocity of the platform when the car started to move, would the equation Ptotal = m1v1 + m2v2 be used (with Ptotal being 0)?
 
  • #9
Stormblessed said:
And to find the velocity of the platform when the car started to move, would the equation Ptotal = m1v1 + m2v2 be used (with Ptotal being 0)?

Yes.
 
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What is momentum?

Momentum is a measure of an object's motion, determined by its mass and velocity. It is a vector quantity, meaning it has both magnitude and direction.

What is the equation for calculating momentum?

The equation for calculating momentum is: momentum = mass x velocity. This can also be written as p = m x v, where p represents momentum, m represents mass, and v represents velocity.

How is momentum conserved in a system?

Momentum is conserved in a system when the total momentum of all objects before a collision or interaction is equal to the total momentum of all objects after the collision or interaction. This is known as the law of conservation of momentum.

How do you find the total momentum of a system?

To find the total momentum of a system, you must first determine the mass and velocity of each object in the system. Then, you can use the equation p = m x v to calculate the momentum of each object. Finally, add up all of the individual momenta to find the total momentum of the system.

Can momentum be lost in a system?

No, momentum cannot be lost in a system. According to the law of conservation of momentum, the total momentum of a system must remain constant. This means that if momentum is transferred from one object to another, the total momentum of the system will remain the same.

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