That implies you do not know how to combine resistances at all. I mean, if you take two series resistance, there is a short circuit (aka "a wire") between the two and it's even worse with parallel resistors since they have short circuits (aka "wires") between pairs of ends.Shawkify said:
NascentOxygen said:
No. Where is your simplified circuit showing the external terminals?Shawkify said:
A Thevenin Equivalent Circuit is a simplified representation of a complex network of resistors, voltage sources, and current sources. It consists of a single voltage source in series with a single equivalent resistance, and can be used to analyze the behavior of a circuit without having to consider the details of the internal components.
To calculate the Thevenin Equivalent Circuit, the circuit is first disconnected from the load and all voltage sources are shorted. The equivalent resistance is then determined by finding the resistance between the two points where the load was connected. The equivalent voltage is found by measuring the voltage across those two points.
The Thevenin Equivalent Circuit is used to simplify complex networks and make circuit analysis easier. It is also useful in predicting the behavior of a circuit under different load conditions and in designing efficient circuitry.
The Thevenin Equivalent Circuit assumes that the internal components of the network are linear and can be represented by a single voltage source and resistance. It also only applies to DC circuits and does not take into account the effects of capacitance or inductance.
No, a Thevenin Equivalent Circuit is only applicable to linear circuits. Non-linear circuits, such as those with diodes or transistors, cannot be simplified in the same way and require more complex analysis methods.