Finding Vector C Using A-2B=pC: Magnitude, Direction, and Components

  • Thread starter damdamct
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In summary: Cy=-26.4|C| = 27.8C direction = 361.9 degrees, not sure if i am rightIn summary, the vectors are related by the equation A-2B=pC, where p is a scalar. The value of p is -1.06, the y-component of C is -26.4, and the magnitude and direction of vector C is not known.
  • #1
damdamct
4
0

Homework Statement


Vector A has a magnitude of 9.10 and is directed at 55.0 degrees. Vector B has a magnitude of 12.5 and is directed at 125 degrees . The x component of vector C is 8.60. The vectors are related by the equation A-2B=pC, where p Is a scalar. Find the value of p , the y component of C and the magnitude and the direction of vector C

Homework Equations


x component = Acos(O)
y component = Asin(O)
magnitude = squaroot of x^2 +y^2
direction =arctan(y/x)

The Attempt at a Solution


i tried to attempt on this problem and got
p=-1.06
Cy=-26.4
|C| = 27.8
C direction = 361.9 degrees, not sure if i am right
 
Last edited:
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  • #2
Ok. I think you need to break this up into steps. First, calculate the x-component for A and B. Then, use what you know to solve for p. After that, you can figure out the rest of C.
 
  • #3
i tried to attempt on this problem and got
p=-1.06
Cy=-26.4
|C| = 27.8
C direction = 361.9 degrees, not sure if i am right
 
  • #4
damdamct said:

Homework Statement


Vector A has a magnitude of 9.10 and is directed at 55.0 degrees. Vector B has a magnitude of 12.5 and is directed at 125 degrees . The x component of vector C is 8.60. The vectors are related by the equation A-2B=pC, where p Is a scalar. Find the value of p , the y component of C and the magnitude and the direction of vector C


Homework Equations


x component = Acos(O)
y component = Asin(O)
direction = squaroot of x^2 +y^2

The Attempt at a Solution


direction = square root of x^2 + y^2? Where did you get this equation?

Hint: what is the magnitude of a vector in terms of its components?
 
  • #5
SteamKing said:
direction = square root of x^2 + y^2? Where did you get this equation?

Hint: what is the magnitude of a vector in terms of its components?

Oops , I am sorry , square root of x^2 + y^2 would be a formula of the magnitude . Direction = arctan(y/x).
Like i said , i have tried to attempt on this problem already and i got some answers on the #2 post above. I am not sure that if those are right the right answers or not. Can someone confirm the answers for me please?
 
  • #6
It's a lot easier for those trying to help if you post all your working, purely symbolically, only substituting numbers at the end.
 
  • #7
so here is what i got
 

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