- #1
Chris Fuccillo
- 19
- 1
Hi again and thank you again for the help
If I have two magnetic fields, one permanent ring magnet B2 free floating on a fixed electromagnetic coil B1 and the field are perpendicular 90 deg to each other will the free floating permanent ring magnet feel a strong magnetic torque and rotate? Ever where I read so far as long as there is a gradient or the field is at an angle greater than 0 deg there is force/torque on the ring magnet. I have not seen an example where the fields are at 90 deg/perpendicular is this special case like when the fields are at 0 deg/ parallel?
B2 = permanent magnetic
B1 = electromagnet coil
F1 = Force/magnetic torque
B2 ↑ B1→ =F1↗
Or
B2 ↓ B1→ =F1↘
If the above is true can you point me to the proper formula for calculating the force. When it comes to the magnetic fields, the distances in the calculations are in millimeters and fractions of a millimeters. I believe this leaves me stuck using formula correct? F(x)= (3μₒ/π) *m1*m1* (1/xˆ4). I think there should be a cos or tan function to it where I am at 90 deg now
If I have two magnetic fields, one permanent ring magnet B2 free floating on a fixed electromagnetic coil B1 and the field are perpendicular 90 deg to each other will the free floating permanent ring magnet feel a strong magnetic torque and rotate? Ever where I read so far as long as there is a gradient or the field is at an angle greater than 0 deg there is force/torque on the ring magnet. I have not seen an example where the fields are at 90 deg/perpendicular is this special case like when the fields are at 0 deg/ parallel?
B2 = permanent magnetic
B1 = electromagnet coil
F1 = Force/magnetic torque
B2 ↑ B1→ =F1↗
Or
B2 ↓ B1→ =F1↘
If the above is true can you point me to the proper formula for calculating the force. When it comes to the magnetic fields, the distances in the calculations are in millimeters and fractions of a millimeters. I believe this leaves me stuck using formula correct? F(x)= (3μₒ/π) *m1*m1* (1/xˆ4). I think there should be a cos or tan function to it where I am at 90 deg now