Hill's law (muscle contraction speed) -- Calculations when lifting different weights

In summary, the conversation discusses the relationship between the force, velocity, and weight when lifting objects. It mentions Hill's law, which explains the detailed relationship between muscle contraction velocity and weight. The conversation also touches on the concept of power and the limits of strength when lifting objects. The main point is that the velocity at which an object can be lifted is limited by both the force and the weight being lifted.
  • #1
John3509
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3

Homework Statement



https://imgur.com/a/OLPyMfK
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Homework Equations


F=ma
W=F*d
W=T2 - T1

The Attempt at a Solution



For part A i figured it must be E because that is the only one that goes to 0 as the hit says.
but nothing about this problem makes any sense to me.

Where it says "You notice that the smaller the weight you attempt to lift, the quicker you can lift it." , I'm thinking, no, you can lift the higher wights just as fast you need need to apply a larger force.

"However, you also notice that there is a limit to how quickly you can lift even very small weights"
Sure, biologically there is a limit to your strength but theoretically should be able to lift infinitely quick by applying an infinitely large force, on a graph this should show the force going to infinity, each individuals biological limit would be then represented by some maximum point of the Force axis (x axis) which they could reach. And the max "quickness" which they could lift it is the y value corresponding with that point in the F axis. So i would expect the graph to be constantly going up, Larger force, can lift it more quickly.

And why is it representing the quickness which you can lift it as velocity on the y-axis not time?

"The detailed relationship between the contraction velocity of a muscle (the speed with which you can lift something) and the weight you are attempting to lift, is known as Hill’s law."

Especially this makes no sense to me, The velocity is not constant, how can you have a velocity out put for every force input when the force is causing an acceleration?

What is this question supposed to test, the impulse momentum theorem? This question is from a chapter before it is covered, F=ma? W=F*d ? I just can't interpret what is going on here
 

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  • #2
John3509 said:
you can lift the higher wights just as fast you need need to apply a larger force.
The scenario is that you are lifting all weights as fast as you can. If you can summon up a greater force to cope with the larger weights, why weren't you using this greater force with the smaller weights?
John3509 said:
biologically there is a limit to your strength
Strength is not the point here. It is a limitation on how fast a muscle can contract.
John3509 said:
why is it representing the quickness which you can lift it as velocity on the y-axis not time?
If all lifts are through the same distance, there is a simple connection between time and average velocity. But with the heavier weights you might not manage the full distance, so it's the velocity that matters, not the time.
Further, as noted, power is force times velocity, and there is a limit to the power the muscle can produce. For the most part, the graph illustrates this relationship, i.e. with the same power available, the velocity is inversely proportional to the force. The differences from that are most noticeable at the extremes. As the force required tends to zero (hmm.. that is ignoring the weight of the arm?), the velocity becomes limited by the maximum contraction rate of the muscle; at the other extreme, it becomes limited by the maximum force the muscle can exert.
 
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What is Hill's law and how does it relate to muscle contraction speed?

Hill's law is a principle in muscle physiology that states that the velocity of muscle contraction is directly proportional to the load or weight being lifted. This means that as the weight increases, the speed of muscle contraction will decrease.

How is Hill's law calculated?

Hill's law is calculated using the formula v = a - bF, where "v" is the velocity of muscle contraction, "a" is the maximum velocity of contraction without any load, "b" is the inverse of the maximum force the muscle can generate, and "F" is the external load being lifted.

Does Hill's law apply to all types of muscle contraction?

Yes, Hill's law applies to both concentric and eccentric muscle contractions. In concentric contractions, the muscle shortens as it contracts, while in eccentric contractions, the muscle lengthens as it contracts. In both cases, the speed of muscle contraction is influenced by the load being lifted.

Can Hill's law be used to predict muscle fatigue?

Yes, Hill's law can be used to predict muscle fatigue. As the load being lifted increases, the speed of muscle contraction decreases, and the muscle will eventually reach a point where it can no longer produce enough force to move the load. This is known as muscle fatigue.

Are there any limitations to Hill's law?

While Hill's law is a useful concept in understanding muscle contraction speed, it does have some limitations. It assumes that the muscle is the only force acting on the load, and does not take into account factors such as muscle fiber type, cross-sectional area of the muscle, and the use of other muscle groups to assist in lifting the load.

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