You have calculated a propulsive force (F), right?AlexPilk said:F=480/125=3.84 N
Weight=mg=600
600-friction=3.84
1.I think so, it's the force that accelerates the sledharuspex said:You have calculated a propulsive force (F), right?
What direction does that act in?
What direction does mg act in?
(You might have noticed that you have not used the 10m height.)
As in vertically down? You obtained it by dividing momentum by time. What direction was the momentum in?AlexPilk said:2.Downwards
The weight of the sled does not have a significant impact on its speed down the hill. The main factors that affect the speed are the angle of the hill, the surface conditions, and any external forces such as friction or wind.
Friction plays a crucial role in the movement of a sled down a hill. It is the force that opposes the motion of the sled and ultimately slows it down. Friction is affected by the surface conditions of the hill, the weight of the sled, and the material of the sled's runners.
Yes, a sled can go faster on a steeper hill. This is because a steeper hill will provide a greater gravitational force, which will accelerate the sled. However, the steepness of the hill also affects the amount of friction and the sled's control, so there is a limit to how steep the hill can be for a sled to go faster.
The shape of the sled can significantly impact its movement down the hill. A streamlined and aerodynamic shape will reduce air resistance and allow the sled to go faster. The shape of the runners also plays a role, as sharp and smooth runners will reduce friction and allow the sled to slide more easily.
The sled's speed will gradually increase as it goes down the hill until it reaches its maximum speed, also known as its terminal velocity. At this point, the gravitational force is balanced by the opposing forces of friction and air resistance, resulting in a constant speed. The speed may decrease if the hill becomes less steep or if there is an increase in friction or wind resistance.