- #1
kptsilva
- 33
- 0
hey guys,
I came across a research paper stating to numerically integrate the following equation.
2/3 a^2 b''[a] + (1 - w[a]) a b'[a] - (1 + w[a]) (1 - 3 c w[a]) b[a]
A Boundary condition is given b'[0.0001]=0
Where;
w[a_] := 2*a^(3*(1 + c))/(1 + 2*a^(3*(1 + c)));
(c=1) (c is a variable but let's consider a particular instance c=1)
'a' goes from 10^-4 to 1000 in a log scale.
I want to plot b[a]/b[0.0001] vs. a
how can i plot this using mathematica?
I came across a research paper stating to numerically integrate the following equation.
2/3 a^2 b''[a] + (1 - w[a]) a b'[a] - (1 + w[a]) (1 - 3 c w[a]) b[a]
A Boundary condition is given b'[0.0001]=0
Where;
w[a_] := 2*a^(3*(1 + c))/(1 + 2*a^(3*(1 + c)));
(c=1) (c is a variable but let's consider a particular instance c=1)
'a' goes from 10^-4 to 1000 in a log scale.
I want to plot b[a]/b[0.0001] vs. a
how can i plot this using mathematica?