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Saladsamurai
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Homework Statement
I need to find the Thevenin equivalent of the circuit shown:
I found the open circuit voltage (VAB) by noting that VAB = V3 and used the voltage division
[tex]V_{AB} = V_s\left ( \frac{R_3}{R_1||R_2 + R_3}\right ) = 12\V[/tex]
I am having a little trouble finding the short circuit current IAB (which comes about by replacing RL with a wire).
The Attempt at a Solution
We can see that the current that comes out of the combined resistance of R1||R2 is what goes into R3 and the length of wire AB. Now it was my reasoning that since the wire AB offers no resistance, then there is no incentive for current to flow through R3 and hence the current through AB would just be:
[tex] I_{AB}=\frac{V_s}{R_1||R_2}[/tex]
but this does not give the correct results.
Any thoughts on this?
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