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Homework Statement
m=100gr
g=9.81 m/s2
H=75m
Combustion of gunpowder = 2.7x10^6 J/Kg
This would mean we only need 0.2gr of gunpowder to get 75m high.
Why is there in a normal rocket more gundpowder?
Our physics and chemistry teacher checked my calculations but couldn't find a mistake, so what is the problem?
Homework Equations
U=m*g*h
---------
U=Joules
M=Kg
g=gravitational acceleration
H=hight in meters
Combustion of gunpowder = 2.7x10^6 J/Kg
Average rocket is 10% efficient
The Attempt at a Solution
U=0.1*9.81*75
U=73.57500J
U*10=735.8J
1000gr | 2.7*10^6
X | 735.8
X=Gunpowder needed
X=1000*735.8/2.7x10^6
X=0.27251851851gr