How to calculate force needed to get a tire spinning

In summary: Read MoreIn summary, the individual is looking for an application or method to calculate the force required to start a tire moving from a dead stop on a side by side/UTV. They want to compare different tire brands and sizes to determine the impact on stress on a transmission. The key factors in this calculation include coefficient of friction, weight on the wheel, wheel diameter, and the tire's rubber compound and footprint on the road. They are seeking objective facts to aid in their decision-making process and have turned to others for help, but are willing to put in the effort to find the answer.
  • #1
sugarray
3
1
I am looking for an application to see how much force is needed to start a tire spinning to compare different sizes and weights of different brands of tires.

This is to help give an idea of stress on a transmission.

I have searched an hour hear as well as Google looking for a formula or calculator, but have been unsuccessful.
 
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  • #2
sugarray said:
I am looking for an application to see how much force is needed to start a tire spinning to compare different sizes and weights of different brands of tires.

This is to help give an idea of stress on a transmission.

I have searched an hour hear as well as Google looking for a formula or calculator, but have been unsuccessful.
Your question is not at all clear. Force from what? Why would this stress the transmission? Get the tire spinning under what conditions? Why would tire brand or size matter?

Please describe exactly the scenario you are trying to analyze.
 
  • #3
I am interested in the force required to start a tire moving from a dead stop on my side by side/UTV.

Using the weight of the tire and the diameter of the tire and maybe the rolling resistance, if published.

I want to compare how weight and size of tire affect the force needed to start a tire rolling. This will allow me to compare say, BF Goodrich/Tusk/Tensor/Sedona tires of 28" and 30" diameters in a standard way to help aid my decision in which tire to purchase.
 
  • #4
The key factors in making this calculation are coefficient of friction, weight on the wheel and wheel diameter.

Here are some hints:

1. If you assume a coefficient of friction between the tire and the surface of the road to be 1 then it will take as much force to slid (spin) the wheel as is pushing down on that wheel.
If you assume a coefficient of 0.50 then it would take only 1/2 the weight on that wheel to slid the tire. BTW-This force is perpendicular to the applied weight and right at the road surface.

2. How do you get this force to be applied right at the interface of the wheel and the road surface?

3. How does the diameter of the wheel fit into the equation?

4. How does the tires’ rubber compound effect the equation?
5. How does the footprint made by the tire on the road effect the equation?
What do you think?
BTW - Do you mean rolling or sliding (spinning)?
 
Last edited:
  • #5
AZFIREBALL said:
The key factors in making this calculation are coefficient of friction, weight on the wheel and wheel diameter.

Here are some hints:

1. If you assume a coefficient of friction between the tire and the surface of the road to be 1 then it will take as much force to slid (spin) the wheel as is pushing down on that wheel.
If you assume a coefficient of 0.50 then it would take only 1/2 the weight on that wheel to slid the tire. BTW-This force is perpendicular to the applied weight and right at the road surface.

2. How do you get this force to be applied right at the interface of the wheel and the road surface?

3. How does the diameter of the wheel fit into the equation?

4. How does the tires’ rubber compound effect the equation?
5. How does the footprint made by the tire on the road effect the equation?
What do you think?

I think I’m not wanting that much specificity. Which was a concern when I posted. It might not be possible to get the information I’m wanting, and that’s ok. I’m just looking for some how to add a little science into my decision process. Everyone has an opinion on which tire is best, but objective facts would be nice.
My physics classes were A LONG time ago. So, I came here for a little help. If that help ends up being that I can’t get the info I’m looking for, then that’s fine. Reading through the posts during my search, you are some smart folks here, so anything helps.
 
  • #6
We expect you to invest a little into the process of finding the answer. Just like in school!
 
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  • #7
sugarray said:
I am interested in the force required to start a tire moving from a dead stop on my side by side/UTV.
Is this tire on the ground or spinning in air? You said "spinning" in your first post. Is the vehicle in gear? What force is making it "spin" - the engine torque? Are you just trying to get the tire to turn or are you really trying to find out what it takes to get the vehicle to move?
Using the weight of the tire and the diameter of the tire and maybe the rolling resistance, if published.

I want to compare how weight and size of tire affect the force needed to start a tire rolling. This will allow me to compare say, BF Goodrich/Tusk/Tensor/Sedona tires of 28" and 30" diameters in a standard way to help aid my decision in which tire to purchase.
Why do you think any of that matters?

Again, you need to put a lot more effort into this, not just so you can learn like in school, but also because with the information you've given us, we literally cannot help you. We have no idea what you are trying to do if you won't tell us. But if making a purchasing decision on the right tire for your vehicle is what you are ultimately after, then the short answer is that none of what you are saying matters.
 
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  • #8
We should first determine if we are looking to solve for rolling resistance or spinning (slipping) resistance, as they are two very different things!
 
  • #9
AZFIREBALL said:
The key factors in making this calculation are coefficient of friction, weight on the wheel and wheel diameter.

Here are some hints:

1. If you assume a coefficient of friction between the tire and the surface of the road to be 1 then it will take as much force to slid (spin) the wheel as is pushing down on that wheel.
If you assume a coefficient of 0.50 then it would take only 1/2 the weight on that wheel to slid the tire. BTW-This force is perpendicular to the applied weight and right at the road surface.

2. How do you get this force to be applied right at the interface of the wheel and the road surface?

3. How does the diameter of the wheel fit into the equation?

4. How does the tires’ rubber compound effect the equation?
5. How does the footprint made by the tire on the road effect the equation?
What do you think?
BTW - Do you mean rolling or sliding (spinning)?
hey azfireball,
how to proceed if i want to calculate the starting torque required for a bike weighing 120 kg and a load of 150kg with tyre specification of 120/70 r12.
 
  • #10
First define 'starting torque'. Do you mean to just start it rolling, or to start it spinning (slipping) while on a surface with a 270 kg load applied? Where is the torque applied...at the wheel or on the pedals?
 
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  • #11
OP has not returned to expand and the recent discussion has prompted a new thread, so I'm closing this.
 

1. What is the formula for calculating the force needed to get a tire spinning?

The formula for calculating the force needed to get a tire spinning is force = mass x acceleration. This means that the force required is directly proportional to the mass of the tire and the rate of its acceleration.

2. How does the weight of the vehicle affect the force needed to get a tire spinning?

The weight of the vehicle plays a significant role in determining the force needed to get a tire spinning. The heavier the vehicle, the more force is required to overcome its inertia and get the tire spinning.

3. Can the surface of the road affect the force needed to get a tire spinning?

Yes, the surface of the road can affect the force needed to get a tire spinning. A rough or uneven surface can create more friction, which means more force is required to get the tire spinning. On the other hand, a smooth surface will require less force.

4. How does the size of the tire affect the force needed to get it spinning?

The size of the tire does not directly affect the force needed to get it spinning. However, a larger tire may have more mass, which means more force is required. Additionally, a larger tire may have a larger contact area with the road, which can affect the friction and therefore the force needed.

5. How can I calculate the force needed to get a tire spinning if I know the torque and angular acceleration?

To calculate the force needed to get a tire spinning if you know the torque and angular acceleration, use the formula force = torque / radius. The radius in this formula refers to the radius of the tire. This formula is derived from the equation torque = force x radius, which can be rearranged to solve for force.

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