- #1
Sneakatone
- 318
- 0
A human cannonball was fired from a cannon with a muzzle velocity of 107 km/h. The firing angle was 45 degrees from the horizontal
Ive converted 107 km/h to 29.71 m/s
1.How many seconds did it take for the human cannonball to reach maximum height?
2.How high did he rise?
h = (V²/4g)=22.5m
3.How far from the cannon did he land?
R = (V²/g) =29.72^2/9.8=90.1m
I cannot seem to find the time for #1 , i tried v/g=29.72/9.8=3.029 and that's wrong,
t = (V/g)√2= 4.28 and that is wrong.
what do I need to do
Ive converted 107 km/h to 29.71 m/s
1.How many seconds did it take for the human cannonball to reach maximum height?
2.How high did he rise?
h = (V²/4g)=22.5m
3.How far from the cannon did he land?
R = (V²/g) =29.72^2/9.8=90.1m
I cannot seem to find the time for #1 , i tried v/g=29.72/9.8=3.029 and that's wrong,
t = (V/g)√2= 4.28 and that is wrong.
what do I need to do