I with the formula for this marble falling from a platform

In summary, the conversation discusses the release of a marble from a platform with an equation for the platform's height. The platform is at a fixed height of 70 meters and the marble is released at a velocity of 22.5 meters per second. The conversation also mentions the need to find an equation for the velocity of the platform and discusses using differentiation to do so.
  • #1
DThes
New user has been reminded to use the Homework Help Template and show their work in the first post
A marble is released at 22.5 meters per second from a 70 meter tall platform. When will the marble strike the ground if the equation for the platforms height is 2.3[t][/2]+ (-)6.5t+70?
 
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  • #2
Welcome to the forum. Please don't delete the Homework template as it's there for a good reason.

In what direction is the marble released?

You have an equation for the height/position of the platform. Do you know how to get an equation for the velocity of an object from the equation for it's position?
 
  • #3
Your question confuses me. Is the platform at a fixed height of 70 meters or is it at a changing height of 2.3[t][/2]+ (-)6.5t+70? Also, why would the platform height matter after the marble is released?
 
  • #4
CWatters said:
Welcome to the forum. Please don't delete the Homework template as it's there for a good reason.

In what direction is the marble released?

You have an equation for the height/position of the platform. Do you know how to get an equation for the velocity of an object from the equation for it's position?
Is it vx= dxf/t?
 
  • #5
FactChecker said:
Your question confuses me. Is the platform at a fixed height of 70 meters or is it at a changing height of 2.3[t][/2]+ (-)6.5t+70? Also, why would the platform height matter after the marble is released?
I am not sure if the platform is at a fixed height. That's the whole the whole problem.
 
  • #6
DThes said:
I am not sure if the platform is at a fixed height.

No the position is varying according to that equation. Note that when you substitute t=0 you get the initial height of 70m. At other values of t you get a different height.

DThes said:
Is it vx= dxf/t?

Yes to go from position to velocity you differentiate the position equation. I suggest you do that and post an equation for the velocity of the platform.
 
  • #7
FactChecker said:
Your question confuses me. Is the platform at a fixed height of 70 meters or is it at a changing height of 2.3[t][/2]+ (-)6.5t+70? Also, why would the platform height matter after the marble is released?

It's not the height that matters it's the velocity. I assume the launch velocity (22.5m/s) is relative to the moving platform.

Correction: The height at launch will matter but it's known to be 70m.
 
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  • #8
CWatters said:
It's not the height that matters it's the velocity. I assume the launch velocity (22.5m/s) is relative to the moving platform.

Correction: The height at launch will matter but it's known to be 70m.
Oh, of course. Thanks.
 
  • #9
DThes said:
Is it vx= dxf/t?
I assume that we are talking about an upward vertical release. So we are talking about vertical position -- aka height. We have the height of the platform as a function of time. We do not have anything that would aptly be called "x" or "f".

How about expressing the platform's vertical velocity as ##v_p(t) = \frac{d\ h_p(t)}{dt}##
 

1. What is the formula for calculating the velocity of a marble falling from a platform?

The formula for calculating the velocity of a marble falling from a platform is v = gt, where v is velocity, g is the acceleration due to gravity (9.8 m/s²), and t is time in seconds.

2. How do you calculate the distance traveled by a marble falling from a platform?

The formula for calculating the distance traveled by a marble falling from a platform is d = (1/2)gt², where d is distance, g is the acceleration due to gravity (9.8 m/s²), and t is time in seconds.

3. What is the acceleration of a marble falling from a platform?

The acceleration of a marble falling from a platform is 9.8 m/s², which is the acceleration due to gravity on Earth.

4. What factors can affect the velocity of a marble falling from a platform?

The factors that can affect the velocity of a marble falling from a platform include the height of the platform, air resistance, and the mass of the marble.

5. How does the velocity of a marble falling from a platform change over time?

The velocity of a marble falling from a platform increases as it falls due to the acceleration of gravity. However, as it reaches its terminal velocity, the velocity will remain constant until it reaches the ground.

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