- #1
ElijahRockers
Gold Member
- 270
- 10
Homework Statement
Derive the following relation, where z1 and z2 are arbitrary complex numbers
|z1z2*+z1*z2| ≤ 2|z1z2|
The Attempt at a Solution
I found the expression |z1z2*+z1*z2| = |2(a1a2+b1b2)| = √(4[a12a22 + 2a1a2b1b2 +b12b22])
But that is where I get stuck. How does the equal sign become an inequality? Also, there are no imaginary terms in my expression, but there ARE imaginary terms in the right hand side, so I think I am doing something wrong.
I also tried doing the derivation using polar forms but it got complicated very quickly.
Thanks.