- #1
asdf1
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for the equation, (a+1)ydx+(b+1)xdy=0,
i am wondering how to get (x^a)(y^b) as an integrating factor~
the following is my work:
(1/F)(dF/dx)=(a-b)/[(b+1)x]
=> F=cx^[(a-b)/(b+1)]
why doesn't that method work?
i am wondering how to get (x^a)(y^b) as an integrating factor~
the following is my work:
(1/F)(dF/dx)=(a-b)/[(b+1)x]
=> F=cx^[(a-b)/(b+1)]
why doesn't that method work?