- #1
MathGnome
- 10
- 0
Ok, so we have
[itex]\int_{0}^{1}\left(\sin{2x}*\cos{2x}\right)dx[/itex]
Using the double angle forumla we change the integrand
[itex](1/2)\int_{0}^{1}\left(2*\sin{2x}*\cos{2x}\right)dx[/itex]
which converts to
[itex](1/2)\int_{0}^{1}\left(\sin{4x}\right)dx[/itex]
This is where I run into trouble... I'm trying to use the formula
[itex]\int\left(\sin{bx}\right)dx = (1/-b)\cos{bx}[/itex]
but my answers are not working. I'm thinking that it has something to do with the fact this is a deffinite integral... any help?
Thx
[itex]\int_{0}^{1}\left(\sin{2x}*\cos{2x}\right)dx[/itex]
Using the double angle forumla we change the integrand
[itex](1/2)\int_{0}^{1}\left(2*\sin{2x}*\cos{2x}\right)dx[/itex]
which converts to
[itex](1/2)\int_{0}^{1}\left(\sin{4x}\right)dx[/itex]
This is where I run into trouble... I'm trying to use the formula
[itex]\int\left(\sin{bx}\right)dx = (1/-b)\cos{bx}[/itex]
but my answers are not working. I'm thinking that it has something to do with the fact this is a deffinite integral... any help?
Thx