- #1
clementc
- 38
- 2
Homework Statement
Hey guys,
This is just a qualitative question.
So assume I have a massive super large magnetic field, and pull a straight, isolated conducting wire sideways through it with constant velocity. I know that the EMF induced is given by
emf = Blv where
l is the length of the conductor
B the magnetic field strength
and v the velocity with which the wire moves
But say I have a square loop entirely in the field, and move it again with velocity v (it still remains entirely in the field)
Is there still emf induced? By Faraday's law, there's no change in flux, so hence there should be no emf. By I just don't know why.
I mean if emf is induced even for an isolated straight wire, why isn't it for a square loop?
I'm thinking it's kind of because the 2 vertical sides of the square loop both have charges trying to move up/down them (depending on the direction B and which way the loop moves), so they kind of "crash" into each other at the top and bottom edges and cancel out each other?
I'm sorry if it's kind of confusing, but does anyone know?
Thank you very much!