Kinematic Equations Problem: Toy cars on adjacent tracks

In summary: Are you familiar with the formula for the distance traveled by an object in a uniform acceleration situation ? If so, how can you use that formula to find the answer in (d) ?In summary, at t = 2.97s, the two toy cars have equal speeds of 4.9cm/s and they pass each other at that time. The difference between questions (a) and (c) is that in question (a), we are only looking for the time when the two cars have equal speeds, while in question (c), we are looking for the time(s) when the cars pass each other. The formula for the distance traveled by an object in a uniform acceleration situation is Δx=Vit+
  • #1
dsfrankl
3
0

Homework Statement


At t = 0, one toy car is set rolling on a straight track with initial position 16.0 cm, initial velocity -3.7 cm/s, and constant acceleration 2.90 cm/s2. At the same moment, another toy car is set rolling on an adjacent track with initial position 10.0 cm, an initial velocity of 4.90 cm/s, and constant zero acceleration.

(a) At what time, if any, do the two cars have equal speeds?
(b) What are their speeds at that time?
(c) At what time(s), if any, do the cars pass each other? (If there is only one time, enter NA in the second blank. If there are two times, enter the smaller time first.)
(d) What are their locations at that time? (If there is only one position, enter NA in the second blank. If there are two positions, enter the smaller position first.)
(e) Explain the difference between question (a) and question (c) as clearly as possible. Write for a target audience of students who do not immediately understand the conditions are different.

Homework Equations


Kinematic equations:

Vf=Vi+at
Δx=Vit+1/2at^2
Vf^2=Vi^2+2aΔx
Δx=1/2(Vf+Vi)t

The Attempt at a Solution


(a) t = 2.97s
(b) v = 4.9cm/s
(c) ?
(d) ?
(e) ?[/B]
 
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  • #2
Hi @dsfrankl, Welcome to Physics Forums.

You'll need to show details about what you've tried. You've given our helpers nothing to work with, and they can't help until you've shown that work.
 
  • #3
Hello dsf, :welcome:

I suppose the question you want to ask is "?"
My question is: how can you calculate (a) with the relevant equations you are listing ? :smile:

PF guidelines require you make a start yourself. Is it clear what you are being asked ? in (c) and (d) ?
 

What are the kinematic equations used for?

The kinematic equations are used to describe the motion of objects, specifically in terms of their displacement, velocity, acceleration, and time.

What is the difference between displacement and distance?

Displacement refers to the change in position of an object from its initial position to its final position, while distance refers to the total length of the path traveled by the object.

How do you calculate acceleration using the kinematic equations?

Acceleration can be calculated using the equation a = (vf - vi) / t, where vf is the final velocity, vi is the initial velocity, and t is the time interval.

Can the kinematic equations be used for objects with changing acceleration?

Yes, the kinematic equations can be used for objects with changing acceleration by breaking the motion into smaller segments with constant acceleration, and then using the equations for each segment.

How can the kinematic equations be applied to the problem of toy cars on adjacent tracks?

The kinematic equations can be used to calculate the velocities and displacements of each toy car as they move along the tracks and collide with each other. Additionally, the equations can be used to determine the acceleration of the cars before and after the collision, and to analyze the motion of the cars in terms of their positions, velocities, and accelerations.

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