- #1
Kavya Chopra
- 31
- 2
Homework Statement
Starting from the center of a circular path of radius R, a particle P chases another particle Q that is moving with a uniform speed v on the circular path. The chaser P moves with a constant speed u and always remains collinear with the centre and location of the chased Q.
a)On what path will P eventually move and how long will it take to reach on that path? Also find out the time taken by P to reach Q
Consider the cases u>v, u<v and u=v
Homework Equations
$$v=\omega r$$ (v here referring to tangential velocity)
$$\frac{d\theta}{dt}=\omega$$
The Attempt at a Solution
I can gather that at every instant P moves along a circle of new radius, growing larger and larger. Due to the collinearity of P, Q and the centre at every instant, the angular velocities of both of them will be the same. And since the speed is constant, due to the equation above the tangential component of u will be increasing and thus the component directed towards the centre will keep on decreasing. So I assume that eventually it will be small enough to be negligible and the particle P will move in a circle.
So, at last we can equate the angular velocities to get the radius of P's path.
(Also, I believe that its path of chasing Q is akin to that of a logarithmic spiral. Please correct me and give the right visualization if I'm wrong)
I could only go about this far. I had the intuition that we can find the time by calculus and used
$$\frac{d\theta}{dt}=\omega$$
But for that to give the correct answer
$$\int_{0}^{\frac{\pi}{2}} d\theta=\frac{\pi}{2}$$
And I can't figure out why these 2 have to be the limits, or even if this method is correct. As for the third part, I have no clue.
I could only make one rather obvious deduction if v>u, P can't reach Q.
Please help me with this.