Laplace transform and tabular integration

In summary, the conversation discusses the use of integration by parts to solve a problem involving e^-st(-s cost bt + b sin bt). One person mentions the use of tabular integration, but the others state that it is not required and that integration by parts is sufficient. They offer to help if the person is having trouble with the integration.
  • #1
robertjford80
388
0

Homework Statement



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The Attempt at a Solution



I can't get the jump to [e^-st(-s cost bt + b sin bt)]/(s^2+b^2)

They say they have to use integration by parts but when e and a trig ratio are involved that requires tabular integration. They're obviously not using tabular integration and I don't see why not.
 
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  • #2
Most classes do not use tabular integration, I've never heard of it. You can use integration by parts (twice, and you must do it correctly (otherwise you will find 0=0)). If you know tabular integration, then you have a technique that many of us do not know.

If you tried the integration by parts, and it did not work, show us your steps and we should be able to give a clue.

Tabular integration is not "required".
 
  • #4
Never heard the name. It's still integration by parts. Show us the steps if you had trouble integrating.

And I think you only have to integrate twice.
 

1. What is the Laplace transform and how is it used in mathematics?

The Laplace transform is a mathematical operation that converts a function from the time domain to the frequency domain. It is often used in solving differential equations and analyzing systems in engineering and physics.

2. What is the purpose of using tabular integration with Laplace transforms?

Tabular integration is used to simplify the process of finding the Laplace transform of a function. It involves breaking down a complex function into simpler parts and using a table of known Laplace transforms to find the overall transform.

3. What are the key properties of Laplace transforms?

The key properties of Laplace transforms include linearity, time shifting, scaling, and differentiation/integration in the time domain. These properties allow for easier manipulation and solving of equations.

4. How can Laplace transforms be useful in solving differential equations?

Laplace transforms can be used to convert a differential equation into an algebraic equation, which is often easier to solve. This is especially useful for solving equations with complex initial conditions.

5. Are there any limitations to using Laplace transforms?

Yes, Laplace transforms are not applicable to all functions. They are only defined for functions that are piecewise continuous and have an exponential order, meaning they do not grow too quickly or oscillate too much. Additionally, Laplace transforms cannot solve differential equations with discontinuous functions or functions with infinite discontinuities.

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