- #1
Leo Liu
- 353
- 156
- Homework Statement
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- Relevant Equations
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a) ONLY
The common way to solve this problem is minimizing the two-variable equation after using the substitution ##z^2=1/(xy)##. Yet I wondered if it is possible to optimize the distance equation with three varibles. So I wrote the following equations:
Distance:
$$f(x,y,z)=s^2=x^2+y^2+z^2$$
$$\begin{cases}f_x=2x\\ f_y=2y\\ f_z=2z\end{cases}\implies (0,0,0) \text{ is a critical point}$$
But the graph of ##xyz^2## says otherwise. Why?
Thank you.