Moment of inertia of a system of masses

In summary, the moment of inertia about an axis through the center of mass of a system consisting of two masses connected by a rod of negligible mass is 1.28 kg m^2.
  • #1
Pablo
16
2

Homework Statement



The moment of inertia about an axis through the center of mass of a system consisting of two masses 3.0 and 5.0 kg connected by a rod of negligible mass 0.8m long is

Homework Equations


[/B]
I = I1 + I2

The Attempt at a Solution



I added all the moments of inertia of the system about the middle (0.4m)

I = m1R^2 + m2R^2 = (m1 + m2) * R^2 = (3 + 5) * 0.4^2 = 1.28

However, 1.28 is not the right answers. Does anyone know where I went wrong?
 
Physics news on Phys.org
  • #2
I am no expert but my syllabus is same
I am trying for practice
(m1+m2)R=m1r1+m2r2
8(R)=3(0)+5(0.8)
8R=4
R=1/2
Mment of inertia=MR^2
=8 1/4
=2 Kg m^2
is this correct please tell me
 
  • #3
Suyash Singh said:
I am no expert but my syllabus is same
I am trying for practice
(m1+m2)R=m1r1+m2r2
8(R)=3(0)+5(0.8)
8R=4
R=1/2
Mment of inertia=MR^2
=8 1/4
=2 Kg m^2
is this correct please tell me
Could you explain what this equation means:

(m1+m2)R=m1r1+m2r2
 
  • #4
Pablo said:
the center of mass of a system

Pablo said:
moments of inertia of the system about the middle (0.4m)
Is that the centre of mass?
 
  • #5
Pablo said:
Could you explain what this equation means:

(m1+m2)R=m1r1+m2r2
Is my answer correct?
Learn this equation which i have given
(m1+m2)R=m1r1+m2r2
where m1 and m2 are the given masses
r1 and r2 are their respective positions
R is the position of center of mass
 
  • #6
The first move is to establish the location of the center of mass. It is the balance point where the torques due to the different weights are equal and opposite. Then the moment of inertia can be calculated as the sum of the m r^2 terms.
 
  • #7
Dr Dr news said:
The first move is to establish the location of the center of mass. It is the balance point where the torques due to the different weights are equal and opposite.
Are torques and weights needed to find the center of mass of this and other systems?
 
  • #8
Another way to find the center of mass is to suspend the body and a plumb bob from the same suspension point and repeat using a different point of suspension. Where the two plumb lines cross is the location of the c.m.
 
  • #9
Dr Dr news said:
Another way to find the center of mass is to suspend the body and a plumb bob from the same suspension point and repeat using a different point of suspension. Where the two plumb lines cross is the location of the c.m.
Isn't there a mathematical way to find the CM using algebra?
 
  • #10
Certainly. If you Google center of mass you will find several equations.
 
  • #11
Dr Dr news said:
Certainly. If you Google center of mass you will find several equations.
I will keep that under advisement. Thanks.
 

What is moment of inertia?

Moment of inertia is a measure of an object's resistance to changes in its rotational motion. It is a property that depends on the mass and distribution of mass within the object.

How do you calculate moment of inertia?

The moment of inertia of a system of masses can be calculated by summing the products of each mass and its squared distance from the axis of rotation. This is represented by the formula I = ∑mr², where I is moment of inertia, m is mass, and r is distance from the axis of rotation.

What factors affect the moment of inertia of a system of masses?

The moment of inertia of a system of masses is primarily affected by the mass and distribution of mass within the system. Objects with larger masses and/or masses located farther from the axis of rotation will have a larger moment of inertia.

Why is moment of inertia important?

Moment of inertia is important in understanding how objects will behave when rotating. It is also used in many practical applications, such as designing rotating machinery and calculating the stability of structures.

Can moment of inertia be negative?

No, moment of inertia cannot be negative. It is a measure of an object's resistance to rotation and therefore must be a positive value. However, it is possible for the moment of inertia to have a negative sign if the axis of rotation is chosen incorrectly in the calculation.

Similar threads

  • Introductory Physics Homework Help
Replies
13
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
873
  • Introductory Physics Homework Help
Replies
21
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
10
Views
2K
  • Introductory Physics Homework Help
Replies
12
Views
965
  • Introductory Physics Homework Help
Replies
9
Views
2K
  • Introductory Physics Homework Help
Replies
8
Views
1K
  • Introductory Physics Homework Help
Replies
8
Views
8K
  • Introductory Physics Homework Help
Replies
4
Views
964
Back
Top