- #1
mybrohshi5
- 365
- 0
Homework Statement
Two identical cars (m = 1350 kg) are traveling at the same speed (25 m/s). Car A is going 30 degrees East of North and car B is going 60 degrees West of North. What is the magnitude of the total momentum of the two-car system.
Homework Equations
p = mv
The Attempt at a Solution
I found the x and y components of the momentum of each car. Then i added the similar components together. So then to find the momentum of the system i took the sqrt of the x and y components squared and added together.
x component car A
1350kg(25m/s)(cos60) = 16875
x component of car B
1350kg(25m/s)(cos30) = 29228
Total x component momentum = 46103y component of car A
1350kg(25m/s)(sin60) = 29228
y component of car B
1350kg(25m/s)(sin30) = 16875
Total y component momentum = 46103so the total momentum of the system is
P_total = sqrt ((46103^2) + (46102^2))
P_total = 65199 kgm/s
This is wrong though.
The correct answer is 47700 kgm/s
Can anyone help me get the right answer.
Thank you :)