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fewill
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1. In tests on Earth a lunar surface exploration vehicle (mass = 5.68 × 103 kg) achieves a forward acceleration of 0.220 m/s2. To achieve this same acceleration on the moon, the vehicle's engines must produce a drive force of 1.42 × 103 N. What is the magnitude of the frictional force that acts on the vehicle on the moon?
G= 6.673*10-11
mEarth= 5.98*1024
mMoon= 7.35*1022
rEarth= 6.38*106
rMoon= 1.74*106
2. F=Gm1m2/r2
3. All I know is that the mass is the same on Earth as it is on the moon. I figured that the frictional force is the opposite of the driving force. I am lost. Please help.
G= 6.673*10-11
mEarth= 5.98*1024
mMoon= 7.35*1022
rEarth= 6.38*106
rMoon= 1.74*106
2. F=Gm1m2/r2
3. All I know is that the mass is the same on Earth as it is on the moon. I figured that the frictional force is the opposite of the driving force. I am lost. Please help.