Motion under influence of a resistive force

In summary, the motion of a body under the influence of the given force is dependent on the value of α, which is a dimensionless constant. When solving the equation of motion, the time for which the motion will come to a stop is given by t = (1/γ)*(V0^1-α)/(1-α), and for all values of γ greater than 1, this time is finite. However, for certain values of α such as 0 or 2, the time turns out to be negative, which is not physically realistic. When considering the special cases of α = -1 and α = 1, the time is finite and v vs t can be plotted accordingly.
  • #1
Ananthan9470
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No template because originally posted in wrong thread
Consider the 1d motion of a body under the influence of the force given by F = -m*γ*vα. m is mass, γ is a constant of appropriate dimension, v is velocity and α is dimensionless constant. The value of α for which the motion will come to a stop in finite time is to be calculated. I solved the equation of motion given by v'' = -γ*vα and got an equation for t given by t = (1/γ)*(V01-α)/(1-α); V0 is the initial velocity. According to this, for all γ>1, time is finite. But the sign of t is negative. Why is this happening? Am I doing something wrong?
 
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  • #2
Your solution for t is correct. What do you get for t if ##\alpha = 0##? Is this a finite time? Is it positive?
 
  • #3
Chestermiller said:
Your solution for t is correct. What do you get for t if ##\alpha = 0##? Is this a finite time? Is it positive?
For ##\alpha = 0## it is positive but what about something like α = 2? It is turning out to be negative unless I am mistaken. right?
 
  • #4
Ananthan9470 said:
For ##\alpha = 0## it is positive but what about something like α = 2? It is turning out to be negative unless I am mistaken. right?
Yes. That's the region that is not physically realistic.

What do you get when ##\alpha = -1##? Is that a finite time? What do you get for v vs t in the special case when ##\alpha = 1##?
 

1. What is motion under influence of a resistive force?

Motion under influence of a resistive force is a type of motion in which an object experiences a force that opposes its motion, known as a resistive force. This force can be caused by various factors such as friction, air resistance, or drag.

2. How does a resistive force affect an object's motion?

A resistive force acts in the opposite direction of an object's motion, slowing it down or eventually bringing it to a stop. The amount of resistive force depends on the object's speed and the type of surface or medium it is moving through.

3. What are some examples of resistive forces?

Some common examples of resistive forces include air resistance, which affects objects moving through the air, and friction, which occurs when two surfaces rub against each other. Water resistance, known as drag, is also a type of resistive force that affects objects moving through water.

4. How can resistive forces be calculated?

The calculation of resistive forces depends on the specific type of force and the properties of the object in motion. For example, air resistance can be calculated using the object's velocity, air density, and surface area. Friction can be calculated using the coefficient of friction and the normal force between two surfaces.

5. How does the presence of a resistive force affect an object's velocity and acceleration?

The presence of a resistive force decreases an object's velocity and acceleration. As the object moves, the resistive force acts in the opposite direction of its velocity, causing it to slow down. This decrease in velocity also affects the object's acceleration, as it takes longer for the object to change its speed or direction due to the resistive force.

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