Need help with solving currents using mesh analysis

In summary, the conversation revolves around solving a circuit problem involving mesh currents using Kirchhoff's Voltage Law (KVL). The problem is not provided, but the equations and attempted solution are discussed. The conversation also addresses verifying the equations and finding the required circuit values.
  • #1
meanmachine
3
0

Homework Statement


2uivnva.png


i can't write the problem text as it is a circuit


2. Homework Equations

I labelled the meshes as clockwise shown on the image
KVL: The sum of voltages around a loop equals zero

The Attempt at a Solution



i1 = 8A

i2: 19(i1 - i2) - 5.54(i2-i3) = 0

i3 = 1.7A (I created a supermesh around the 1.7A current source - inside the BLUE square)
Supermesh equation => i3 - i4 = 1.7A

i4 = 0

i5: (I used KVL around the outside of the blue square)
5.54(i2 - i3) -0.5i3 - 0.29(i4 - i5) -12.6(i4 - i5) - 0.5i3

Can some verify these equations and check they are correct?
 
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  • #2
meanmachine said:

Homework Statement


2uivnva.png


i can't write the problem text as it is a circuit
But you can at least state what circuit values are required, right? Is it just the mesh currents? Some particular voltage drops? Maybe the power consumed by certain components? Don't leave us guessing!

2. Homework Equations

I labelled the meshes as clockwise shown on the image
KVL: The sum of voltages around a loop equals zero

The Attempt at a Solution



i1 = 8A

i2: 19(i1 - i2) - 5.54(i2-i3) = 0

Okay so far...

i3 = 1.7A (I created a supermesh around the 1.7A current source - inside the BLUE square)
Supermesh equation => i3 - i4 = 1.7A

i4 = 0
Your supermesh constraint equation is good but your "conclusion" that i3 = 1.7A is unfounded. How did you conclude that i3 = 1.7A and that i4 = 0?

i5: (I used KVL around the outside of the blue square)
5.54(i2 - i3) -0.5i3 - 0.29(i4 - i5) -12.6(i4 - i5) - 0.5i3
No, that doesn't look right; it's not even an equation (no "=" sign). Check what current is actually flowing through the 500m resistors; Looks like i4 to me. Also, what happened to the voltage source in the the supermesh loop? Also, you need to write a separate equation for the i5 loop; Two voltages sources there!
 

Related to Need help with solving currents using mesh analysis

1. What is mesh analysis and how is it used in solving currents?

Mesh analysis is a method used to analyze electrical circuits and determine the currents flowing through each branch. It involves dividing the circuit into smaller, closed loops called meshes and applying Kirchhoff's Voltage Law (KVL) to each mesh. The resulting equations can then be solved to determine the currents in the circuit.

2. How is mesh analysis different from other methods of circuit analysis?

Mesh analysis is different from other methods, such as nodal analysis, because it focuses on the voltage drops across each element in the circuit rather than the node voltages. This can be advantageous for more complex circuits with multiple voltage sources.

3. What are the steps involved in solving currents using mesh analysis?

The steps for solving currents using mesh analysis are as follows:
1. Identify the meshes in the circuit
2. Apply KVL to each mesh to create equations
3. Solve the resulting equations to determine the mesh currents
4. Use Ohm's Law to calculate the currents in each branch of the circuit.

4. Can mesh analysis be used for circuits with dependent sources?

Yes, mesh analysis can be used for circuits with dependent sources. The dependent source is treated like any other element in the circuit and the same steps for mesh analysis can be applied.

5. Are there any limitations to using mesh analysis for circuit analysis?

While mesh analysis is a powerful method for solving currents in circuits, it does have some limitations. It can only be used for circuits with independent sources and linear elements. Additionally, it may not be the most efficient method for circuits with a large number of meshes.

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