Negative sign in Newton's Law of Viscosity?

  • #1
curious_ocean
36
7
TL;DR Summary
Sometimes there is a negative sign and sometimes there is not?
Hi Physics Forums,

I'm wondering why Newton's Law of Viscosity sometimes has a negative sign in front of the viscosity and sometimes it doesn't?

Thanks for your help!
 
Engineering news on Phys.org
  • #2
It depends on whether stresses are considered positive if compressive or extensive, and how. this sign convention is used in determining the force exerted by A on B or by B on A.
 
  • Like
Likes curious_ocean
  • #3
Thanks for responding Chestermiller,

I'm trying to understand the analogies between Fick's 1st Law of Mass Diffusion and Fourier's Law of Heat Conduction.

In the case of Fick's 1st Law the diffusive mass flux happens in the direction opposite to the concentration gradient, smoothing out concentration gradients rather than amplifying them. In Fourier's Law the heat flux is in the direction opposite of the temperature gradient, smoothing out temperature gradients. It makes sense to me that Newton's Law of viscosity would be a "diffusion" of momentum, where gradients in momentum are also smoothed out, but I'm not sure how to draw that diagram.

I'm not quite sure how to interpret your explanation because Newton's Law of viscosity deals with a shear stress, not a normal stress? Is the sign convention discrepancy something like the attached? Where it depends on whether your shear stress is operating on the top or bottom of your infinitely small fluid parcel?

Thanks for your help!
 

Attachments

  • shear_stress.png
    shear_stress.png
    6.3 KB · Views: 33
  • #4
In my googling I found something that says the momentum flux and shear stress have opposite signs... I wonder if this is where my answer lies...

So for the red stress in the picture I drew before (attached above)...Imagine that there are solid plates on the top and bottom of a fluid column. The top plate is moving to the right and the bottom plate is stationary. The force of the top plate on the fluid is applied to the top of a fluid parcel in the positive x direction. $$TauFluidParcelTop_{zx} > 0$$. The force of the fluid on the top plate is in the opposite direction $$TauTopPlate_{zx} < 0$$

If we think of the fluid column as being composed of fluid layers then the force of the fluid above acting on the top of the fluid parcel below is in the positive x direction. $$TauFluidParcelTop_{zx} > 0$$. The force of the fluid below acting on the bottom of the parcel above is in the opposite direction $$TauFluidParcelBottom_{zx} < 0$$.

If the bottom of the fluid parcel (or the next fluid parcel below) also was dragged a bit to the right due to the fluid having some viscosity, there would be a flux of x-momentum in the negative z-direction. So $$MomentumFlux_{zx} < 0$$. This would cause a positive velocity gradient in the positive z direction (velocity is more positive at the top of the fluid column.) So $$ \frac{d (\rho u_x)}{dz} > 0$$. I believe this is where I get the Fickian relationship that is analogous to Fick's 1st Law of Diffusion and Fourier's Law. When I write it this way I preserve the negative sign in the analogy. So we get $$MomentumFlux_{zx} = - \nu \frac{d (\rho u_x)}{dz} $$

To continue on with the scenario...Then the parcel on the bottom of the fluid column would also impart a force on the top of the bottom plate. It is applied to the top of the plate in the positive x direction. So $$TauBed_{zx}>0$$. This force imparted to the bed per unit area is often called the bed stress. So we would get $$ TauBed_{zx} = + \nu \frac{d (\rho u_x)}{dz} |_{z=0} $$. In this version of the equation there is no negative sign.
 
Last edited:
  • #5
I had my tensor notation messed up. The first index should be the direction of the velocity and the second index should be the surface it is fluxing through.
 
  • #6
Chestermiller I think I understand what you meant now.



The sign also determines whether the force is the deforming force (plate acting on fluid) or restoring force (fluid acting on plate).
 
  • #7
See Appendix A of Transport Phenomena by Bird et al. Also Google Cauchy Stress Relationship.
 
  • #8
Thanks, I have plenty of good texts to reference (including Bird et al.) but they are not always the most user friendly. I'm curious what folks think about the momentum flux relationship to the shear stress. Am I on the right track there?
 

1. Why is there a negative sign in Newton's Law of Viscosity?

The negative sign in Newton's Law of Viscosity represents the direction of the force opposing the motion of the fluid. It indicates that the viscous force acts in the opposite direction to the velocity of the fluid.

2. What would happen if the negative sign in Newton's Law of Viscosity was removed?

If the negative sign in Newton's Law of Viscosity was removed, the viscous force would act in the same direction as the velocity of the fluid. This would lead to incorrect predictions and interpretations of fluid flow behavior.

3. How does the negative sign affect the calculation of viscous forces?

The negative sign in Newton's Law of Viscosity ensures that the viscous force is correctly calculated as opposing the motion of the fluid. Without the negative sign, the calculation would result in inaccuracies and inconsistencies in fluid dynamics analysis.

4. Is the negative sign in Newton's Law of Viscosity always necessary?

Yes, the negative sign in Newton's Law of Viscosity is always necessary to accurately describe the behavior of viscous fluids. It plays a crucial role in determining the direction of the viscous force and its impact on fluid flow.

5. Can the negative sign in Newton's Law of Viscosity be interpreted differently?

No, the negative sign in Newton's Law of Viscosity has a specific meaning and interpretation in the context of fluid dynamics. It consistently indicates the direction of the viscous force opposing the motion of the fluid, and any alternative interpretation would lead to incorrect results.

Similar threads

  • Introductory Physics Homework Help
Replies
2
Views
482
Replies
0
Views
948
Replies
12
Views
2K
  • Materials and Chemical Engineering
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • General Engineering
Replies
11
Views
2K
  • Materials and Chemical Engineering
Replies
1
Views
3K
Replies
44
Views
1K
  • Materials and Chemical Engineering
Replies
1
Views
4K
Back
Top