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mom2maxncoop
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Homework Statement
Two ropes are attached to a log that is floating in the water. A force of 80.0 N is applied to one rope and a force of 60.0 N is applied to the other rope, which is lying at an angle of 40° from the first rope. What is the net force on the log?
We know that the angle between the two known vectors is 140°.
Homework Equations
Cosine law:
c2=a2+b2-2abCosC
Sine Law:
sinA/a= SinB/b
The Attempt at a Solution
Cosine Law:
c²=a²+b²-2abCosC
c²=[(80.0)²+[60.0]²-2(80.0)x(60.0)cos140]
c=[80)²+(60)²-2(80)x(60)cos14]^½
c=131.346828
c=132 N
Now to find the angle between the resultnt force vector and the 80.0 N vector, use sine law
sinA/a = sinB/b = sinC/c
sinA/60.0 N = sin140°/132 N
sinA/60.0 N x 60.0 = sin140/132 x60.0
sinA =sin140/132 x 60.0
sinA = 0.292176186
A= sin[itex]^{-}[/itex]0292176186
would that be correct??