Normality of (COONa)2 - KMNO4 titration (redox reaction)

  • #1
Man0uzz
1
0
We used 14ml of a KMNO4 solution of 0.01 Normality, to find the Normality of a (COONa)2 solution.
If we took 10ml of the (COONa)2 solution, what should its Normality be?

I thought about using the following equation: N1V1=N2V2

Does the stoichiometry of the redox reaction affect the equation above? Should we multiply N2V2 with 5/2 because of it?
 
Chemistry news on Phys.org
  • #2
Most likely 0.01N permanganate is actually 0.002M (five equivalents per mole), and normality of oxalate is twice its concentration (two equivalents per mole in redox reactions). If so equation as written should work with no additional stoichiometric coefficients.

But you are right that normality can be ambiguous and sometimes depends on the context, so treat above just as a guess.
 
  • #3
Borek said:
normality can be ambiguous
AAmmmeeeennnnn.
 
  • #4
Borek said:
But you are right that normality can be ambiguous and sometimes depends on the context, so treat above just as a guess.
And I think therefore its use is discouraged for at least 40 years by IUPAC and other organizations...
 

What is the purpose of using KMnO4 in the titration of (COONa)2?

The purpose of using potassium permanganate (KMnO4) in the titration of sodium oxalate ((COONa)2) is to act as an oxidizing agent. KMnO4 has a strong oxidizing power and in acidic medium, it reacts with the reducing agent sodium oxalate, which acts as the titrant. This reaction helps in determining the concentration of the oxalate in the solution.

How do you prepare the solution for a (COONa)2 - KMnO4 titration?

First, accurately weigh a sample of sodium oxalate and dissolve it in distilled water to make a known concentration of the solution. Then, prepare a KMnO4 solution of known molarity. Add a few drops of a dilute sulfuric acid to the oxalate solution to provide the acidic medium necessary for the KMnO4 to act as an oxidizer. The solution is now ready for titration.

What is the endpoint in the titration of (COONa)2 with KMnO4?

The endpoint in the titration of sodium oxalate with potassium permanganate is marked by a permanent light pink color that persists for about 30 seconds. This color change occurs when a slight excess of KMnO4 is present in the solution, indicating that all the oxalate ions have been oxidized by the KMnO4.

What is the stoichiometry of the reaction between (COONa)2 and KMnO4?

The stoichiometry of the reaction between sodium oxalate ((COONa)2) and potassium permanganate (KMnO4) in an acidic medium typically follows a 2:5 molar ratio. Here, 2 moles of KMnO4 react with 5 moles of oxalate ions (C2O4^2-). The balanced chemical equation for the reaction is: 2MnO4^- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O.

How do you calculate the concentration of (COONa)2 using the titration data?

To calculate the concentration of sodium oxalate in the solution, use the titration data to first determine the volume of KMnO4 used to reach the endpoint. Apply the stoichiometry of the reaction (from the balanced chemical equation) to relate the moles of KMnO4 to the moles of (COONa)2. Since the volume and molarity of KMnO4 are known, you can calculate the moles of KMnO4 used, and hence, using the molar ratio, find the moles of sodium oxalate. Finally, divide the moles of sodium oxalate by the volume of the sodium oxalate solution to find its concentration.

Similar threads

Replies
2
Views
3K
Replies
1
Views
3K
  • Biology and Chemistry Homework Help
Replies
1
Views
1K
  • Biology and Chemistry Homework Help
Replies
4
Views
21K
  • Biology and Chemistry Homework Help
Replies
10
Views
2K
Replies
1
Views
6K
  • Biology and Chemistry Homework Help
Replies
1
Views
2K
Replies
1
Views
2K
Replies
19
Views
3K
Back
Top