- #1
Misheel
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Homework Statement
mass "m" object is located near the origin of the coordinate system. External force was exerted on the object depending on the coordinate by the formula of Fx=-4*sin(3*pi*x). Find the short oscillation period, and the potential energy depending on the coordinate.
Homework Equations
F=ma
The Attempt at a Solution
I am not really sure what is the short oscillation period... but
since there is only 1 force:
F=Fx=ma
-4sin(3*pi*x)=m*(d^2*x)/dt^2
and assuming that the object will move very little (because it's said to be SHORT osccilation period ?)
sin(3*pi*x) is approximately 3*pi*x .
and since
-ω2*x=(d^2*x)/dt^2 is the formula of the harmonic oscillation :
we find ω=12*pi/m
and the T=2*pi*√(m/(12*pi)) ?
and also assuming that in SHORT oscillation :
it is almost like a spring :
F=-12*pi*x=-kx
k=12*pi
potential energy is Ep= k*x^2/2=6*pi*x^2 ?