That's not really the full problem statement, and a diagram would help, but it sounds like you have a parallel plate capacitor with a dielectric slab filling some fraction of the separation distance?physconomic said:Homework Statement:: Represent the system as the superposition of a polarized dielectric slab and a vacuum capacitor to find the total electric field in the capacitor in terms of Q and the polarisation P. Then find the relationship between the displacement vectorD and Q.
Relevant Equations:: Lorentz field? E=q/(A*sigma0)
Not sure how to set this question up or how to get to the second half
Hi sorry yes it's just a standard parallel plate capacitor with a linear dielectric material filling the whole gap. Thank you though.berkeman said:That's not really the full problem statement, and a diagram would help, but it sounds like you have a parallel plate capacitor with a dielectric slab filling some fraction of the separation distance?
If so, just model it as two capacitors in series -- one with the dielectric in it, and one with vacuum. Once you do that, just use the traditional equations for the charge on a capacitor versus voltage and capacitance, and the equation for the series combination of capacitors...
A parallel plate capacitor with dielectric connected to a battery is a type of electrical circuit that consists of two parallel plates separated by a dielectric material and connected to a battery. The capacitor stores electrical energy and the battery provides the necessary voltage for the capacitor to function.
The capacitor works by storing electrical energy in the form of an electric field between the two plates. When the battery is connected, it creates a potential difference between the plates, causing electrons to accumulate on one plate and leave the other. The dielectric material between the plates helps to increase the capacitance of the capacitor, allowing it to store more charge.
The dielectric material serves to increase the capacitance of the capacitor by reducing the electric field between the plates. This allows for a larger amount of charge to be stored on the plates, increasing the overall energy storage capacity of the capacitor.
The capacitance of a parallel plate capacitor with dielectric can be calculated using the formula C = εA/d, where C is the capacitance, ε is the permittivity of the dielectric material, A is the area of the plates, and d is the distance between the plates. The permittivity of the dielectric material is a measure of how well it can store electrical energy.
Parallel plate capacitors with dielectrics are commonly used in electronic circuits for energy storage, filtering, and voltage regulation. They are also used in power factor correction, where they help to improve the efficiency of electrical systems. Additionally, they are used in various electronic devices such as radios, televisions, and computers.