Particle moving in electromagnetic field - converting units

In summary, the conversation discusses how the equation F = qv × B can be used to prove that a magnetic field pointing perpendicular to the velocity of a charged particle produces a centripetal force. This is equivalent to the equation pc = ABρ, where B is the magnetic field strength and ρ is the radius of the circular orbit. The value of the constant A, in units of GeV/T-m, is then calculated for a proton. The suggested approach is to first demonstrate circular motion, and then do the calculation in GeV units. Alternatively, dimensional analysis can be used to convert the units to Joules/(Tesla-meters) and then convert to GeV using the usual conversion factor.
  • #1
bossman27
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0

Homework Statement


Show that the force on a moving charged particle F = qv × B
from a magnetic field pointing perpendicular to the velocity produces a centripetal force and that this is equivalent to the equation pc = ABρ, where B is the magnetic field strength (in Tesla) and ρ is the radius of the circular orbit (in meters). If we express p in GeV/c, what
is the value of the constant A (which has units GeV/T-m) for a proton?


Homework Equations





The Attempt at a Solution



I had no trouble with the first part of the problem. Since v is perpendicular to B, I just used F=(mv^2)/r and then multiplied both sides by c to get pc = qcB(rho). Now I have A = qc = 1.6x10^-19 C x c, however this is my first time working with eV units and am a bit lost on how to go about converting 'charge*c' to GeV/T-m.
 
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  • #2
Your first step is to demonstrate circular motion.

After that, do your calculation in GeV from the get-go. note that mc2=0.938GeV

[tex]evB=\frac{mv^2}{r}=\frac{p^2}{mr}=\frac{(pc)^2}{mc^2r}[/tex]

Or do the dimensional analysys on your units (Cm/s) to make sure they come out to Joules/(Tesla-meters) then just convert the Joules to GeV by the usual conversion factor.
 

Related to Particle moving in electromagnetic field - converting units

1. What is the equation for calculating the force on a charged particle moving in an electromagnetic field?

The equation for calculating the force on a charged particle in an electromagnetic field is given by F = q(E + v x B), where q is the charge of the particle, E is the electric field, v is the velocity of the particle, and B is the magnetic field.

2. How do you convert units for electric and magnetic fields?

To convert units for electric and magnetic fields, you can use the following conversions: 1 Tesla (T) = 1 N/C * m/s, 1 Gauss (G) = 1 T * 10^4, 1 Volt/meter (V/m) = 1 N/C.

3. How does the direction of the magnetic field affect the motion of a charged particle?

The direction of the magnetic field affects the motion of a charged particle in that it causes the particle to experience a force that is perpendicular to both its velocity and the direction of the magnetic field. This results in the particle moving in a circular or helical path.

4. Can the electric field alone affect the motion of a charged particle?

No, the electric field alone cannot affect the motion of a charged particle. This is because the electric field only exerts a force on a charged particle when it is in motion, whereas the magnetic field can affect the motion of a charged particle even when it is at rest.

5. What is the relationship between the Lorentz force and the velocity of a charged particle?

The Lorentz force on a charged particle is directly proportional to its velocity. This means that as the velocity of the particle increases, the magnitude of the Lorentz force also increases. Additionally, the direction of the Lorentz force is always perpendicular to the direction of the particle's velocity.

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