Particle through magnetic field

[BadatPhysicsguy]

Homework Statement

A particle enters perpendicular to a magnetic field with a speed of 100,000 m/s. The magnetic field has a strength (B) of 0.80 T. The particle starts doing a spinning motion with an 0.1m radius. The particle charge is +3e (three elementary charges). Calculate the mass of the particle.

Homework Equations

Since it does a spinning motion, we need the formula for centripetal motion. F=m(v^2/r). We also need a formula that gives us F based on B and Q (charge) and v (speed). For that we have F = QvB.

The Attempt at a Solution

We set them equal.

m(v^2/r)=QvB and we can take off one v.
m(v/r)=QB, we move the things around so we have m alone
m*v = rQB => m = rQB / v

We enter everything that is known and we get:

0.1 * (3*1.6*10^-19) * 0.80 split by 100,000.

Result: 3.84 × 10^-25 kg. Am I correct?

 

[cheah10]

Before we answer your question, do you think you are correct?

 

[BadatPhysicsguy]

Before we answer your question, do you think you are correct?

I do!

 

[cheah10]

Ok, actually whenever you believe you are correct, you should just be confident and not doubt yourself.
You are correct in this question!

 

[HalfLostAndSearching]

I would first commend you on your use of the correct equations and your clear explanation of your approach. Your calculations seem correct and your final answer of 3.84 × 10^-25 kg appears to be reasonable. However, it is always important to double check your calculations and units to ensure accuracy. Additionally, it would be helpful to provide some context or background information about the particle and its behavior in the magnetic field. Overall, great job on solving the problem!