Photoelectric effect questions: photon absorption and electron ejection....

In summary, the conversation discusses the photoeffect and the absorption of photons by electrons in metal. It is explained that in the photoeffect, the entire system the electron is bound to is impacted by the photon, resulting in the electron becoming free. It is also clarified that with a free electron, the most simple reaction is elastic scattering, also known as the Compton effect. The concept of a zero work function is also discussed, with the conclusion that it is not possible due to energy-momentum conservation. The recommended approach to studying the photoeffect is through a semiclassical approximation and first-order time-dependent perturbation theory.
  • #1
Sandeep T S
67
0
Is a photon fully absorbed by a electron in metal?
Ejected electron is a free electron or bonded one?
Is it possible to have a zero work function? If not why?
I want to study about this detaily ,can you prefer some reference papers?
 
Physics news on Phys.org
  • #2
The photon is fully absorbed in the photoeffect (that's the definition of the photoeffect). It's absorbed by the entire system the electron is bound to before the "impact" of the photon (i.e., the electromagnetic wave). With a free electron you cannot have the photoeffect due to energy-momentum conservation together with the "on-shell conditions" for the particles. In this case the most simple possible reaction is elastic scattering between the free electron and the photon. This is the Compton effect. In the photoeffect after the reaction the electron is free. Zero work function is not possible since the electron must be bound before the photon hits it. That's again due to energy-momentum conservation.

The most simple correct (!) explanation is the treatment where the electron is quantized and the electromagnetic wave treated classically (i.e., the semiclassical approximation in quantum optics) and the use of first-order time-dependent perturbation theory. You find a treatment in my Insights article (which also explains why the old-fashioned teaching of the photoeffect as being a proof for the existence of little particle-like objects called "photons" is wrong and thus evil misleading didactics):

https://www.physicsforums.com/insights/sins-physics-didactics/
 

1. What is the photoelectric effect?

The photoelectric effect is the phenomenon where electrons are emitted from a material when it is exposed to light. This was first observed by Heinrich Hertz in 1887 and later explained by Albert Einstein in 1905.

2. How does the photoelectric effect work?

When a photon of light hits a material, it transfers its energy to an electron in the material. If the energy of the photon is greater than the energy required to overcome the binding energy of the electron, the electron will be ejected from the material.

3. What factors affect the photoelectric effect?

The photoelectric effect is affected by the intensity of the light, the frequency of the light, and the characteristics of the material, such as its work function and the number of free electrons present.

4. What is the work function in the photoelectric effect?

The work function is the minimum amount of energy required to remove an electron from the surface of a material. It is different for each material and is a key factor in determining whether the photoelectric effect will occur.

5. What are some applications of the photoelectric effect?

The photoelectric effect is used in various technologies, such as photovoltaic cells for solar energy, photoelectric sensors in electronic devices, and photoelectric tubes in photocopiers and television cameras. It also played a crucial role in the development of quantum mechanics and our understanding of the nature of light.

Similar threads

Replies
5
Views
648
  • Quantum Physics
Replies
12
Views
743
Replies
5
Views
1K
Replies
13
Views
1K
Replies
5
Views
3K
Replies
4
Views
904
Replies
8
Views
914
  • Quantum Physics
Replies
21
Views
1K
Replies
30
Views
2K
  • Quantum Physics
Replies
4
Views
880
Back
Top